Quantitative Aptitude - Arithmetic Ability Questions

Q:

A box weighs 8.5 kg when full of sand and weighs 5.5 kg when it is half filled with sand . Weight of the empty box is

A) 5 kg B) 6 kg
C) 2.5 kg D) 4.5 kg
 
Answer & Explanation Answer: C) 2.5 kg

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Q:

A bookseller bought 500 text books for  20,000. He wanted to sell them at a profit so that he get 50 books free. At what profit percent should he sell them?

A) 10 B) 20
C) 15 D) 10.5
 
Answer & Explanation Answer: A) 10

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

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Q:

On a certain principal if the Simple interest for two years is Rs 3000 and Compound interest for the two years is Rs 3225, what is the rate of Interest?

A) 7.5 percent B) 30 percent
C) 15 percent D) 22.5 percent
 
Answer & Explanation Answer: C) 15 percent

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Filed Under: Simple Interest
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Q:

If the radius of a circumscribed circle in an equilateral triangle is 14 cm. Then what will be the radius (in cm) of the inscribed circle?

A) 7 B) 14
C) 28 D) 35
 
Answer & Explanation Answer: A) 7

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Filed Under: Area
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Q:

The marked price of an article is Rs. 5000. But due to a special festive offer a certain percent of discount is declared. Mr. X availed this oppurtunity and bought the article at reduced price. He then sold it at Rs. 5000 and thereby made a profit of 11 1/9%. The percentage of discount allowed was?

A) 10 B) 10/3
C) 15/2 D) 100/9
 
Answer & Explanation Answer: A) 10

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Filed Under: Percentage
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Q:

Which of the fractions given below, when added to 5/8, gives 1?

A) 6/16 B) 5/2
C) 6/24 D) 6/3
 
Answer & Explanation Answer: A) 6/16

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Filed Under: Decimal Fractions
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Q:

Mr. Rajesh buys a toy for Rs. 27.50 and sells it for Rs. 28.60. Find the gain %.

A) 5% B) 4%
C) 6% D) 3%
 
Answer & Explanation Answer: B) 4%

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Q:

In each of the following questions two equations I and II are given. Solve both the equations and give answer:
I. x2+2x-195=0II. y2+30y+225=0

A) x = y or relation can’t be established between x and y B) x > y
C)  x < y D)  x ≥ y
 
Answer & Explanation Answer: D)  x ≥ y

Explanation:

 I. x2 + 2x - 195 = 0 = (x+15) (x-13) => x = -15, 13

II. y2 + 30y + 225 = 0 = (y+15) (y+15) => y = -15, -15

So x ≥ y

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