Quantitative Aptitude - Arithmetic Ability Questions

Total quantity of petrol consumed in 3 years =(4000/7.50+4000/8+4000/8.50)  liters

                                                         = 4000(2/15+1/8+2/17) liters                                                   

                                                         = 76700/51 liters

Total amount spent = Rs. (3 x 4000) = Rs. 12000.

Average cost = Rs. (12000*51/76700) = Rs. 7.98.

Let the first number be x,

Then, sum of the four numbers = x + 4x = 5x.

so,  5x/4 = 60 or x = (60 * 4) / 5 = 48.

Area of the wet surface = [2(lb + bh + lh) - lb] 

= 2(bh + lh) + lb 

= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4]m2  

= 49m2

Here, n(S) = 52.

Let E = event of getting a queen of club or a king of heart.

Then, n(E) = 2.

P(E) =n(E)/n(S)=2/52=1/26.

The year 2007 is an ordinary year. So, it has 1 odd day.

1st day of the year 2007 was Monday

1st day of the year 2008 will be 1 day beyond Monday

Hence, It will be Tuesday.

To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.

While A covers 3 m, B covers 4 m.

While A covers 360 m, B covers (4/3)*360 = 480 m.

Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.

 A wins by 20 m.