Quantitative Aptitude - Arithmetic Ability Questions

It is given that the initial amount invested in scheme A is Rs P at 10%per Annum S.I. =PTR/100 = P x 10 x 2/100 Now the total amount after 2 years is = 1.2P New Rate of interest = 12% per annum Time = 5 years S.I for next 5 years when new principal amount is 1.2 P = 1.2Px12x5/100 = 0.72P Total amount after 5 years at 12% per annun = 1.72P Given that 1.72P - 1.2P = 1300 P = 1300/0.52 P = Rs. 2500

a/(b+c) = b/(c+a) = c/(a+b)

Taking reciprocal and adding 1 to each ratio we get;

(b+c)/a + 1 = b/(c+a) + 1 = c/(a+b) + 1

Or (a+b+c)/a = (a+b+c)/b = (a+b+c)/c

So this can only be equal when a=b=c or a+b+c = 0

When a=b=c we get

a/(b+c)= ½When a+b+c = 0 we get

b+c = -a

So a/(b+c) = -1

So the ratios are ½ or -1

I. 2x2 - 13x - 189 = 0 2x2 - 27x + 14x - 189 = 0 x(2x - 27) + 7(2x - 27) = 0 x = -7, 27/2

II. 2y2 - 3y - 189 = 0 2y2 - 21y + 18y - 189 = 0 y(2y - 21) + 9(2y - 21) = 0 y = -9, 21/2

When x, as well as y, have both positive and negative values then no relationship can be established between them because if we consider x to be positive then the negative value of y will be lesser than x. If we consider x to be negative then positive value of y will be greater than x.