Quantitative Aptitude - Arithmetic Ability Questions

Q:

133of 166of133of166 of 10000 of a number will be what percentage of that number?

 

A)  2.32 B)  1.32
C)  0.232 D) 0.0232
 
Answer & Explanation Answer: A)  2.32

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

16 41065
Q:

Simple interest on a certain sum is 16/25 of the sum. Find the rate percent and time, If both are numerically equal.

A) Rate = 7% and Time = 7 years. B) Rate = 8% and Time = 8 years.
C) Rate = 6% and Time = 6 years. D) Rate = 5% and Time = 5 years.
 
Answer & Explanation Answer: B) Rate = 8% and Time = 8 years.

Explanation:

Let sum = X. Then S.I = 16x/25

 

Let rate = R% and Time = R years.

 

Therefore,  (x * R * R)/100 = 16x/25   =>  R = 40/5 = 8

 

Therefore, Rate = 8% and Time = 8 years.

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Filed Under: Simple Interest
Exam Prep: GRE

112 40983
Q:

Find the odd one out of the floowing number series?

270, 261, 279, 252, 289, 243

A) 270 B) 279
C) 289 D) 243
 
Answer & Explanation Answer: C) 289

Explanation:

Here the given number series is 270, 261, 279, 252, 289, 243

270 - 9 = 261

261 + 18 = 279

279 - 27 = 252

252 + 36 = 288 (not equals to 289)

288 - 45 = 243

 

Hence, the odd number in the given number series is 289.

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5 40904
Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only
 
Answer & Explanation Answer: D) Either II or III only

Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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0 40795
Q:

x and y are integers

x + y < 11 , and x > 6

What is the smallest possible value of x - y ?

A) 1 B) 24
C) 4 D) -2
 
Answer & Explanation Answer: C) 4

Explanation:

The smallest value will be obtained by giving x the smallest possible value while y gets the largest possible value. The smallest value for x = 7. This means that y will have to be less than or equal to 3 (so that x + y <11), but we want the largest value of y which is 3.

The difference, x - y will be 4.

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Filed Under: Problems on Numbers
Exam Prep: GRE

4 40744
Q:

On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?

A) Tuesday B) Saturday
C) Friday D) Sunday
 
Answer & Explanation Answer: D) Sunday

Explanation:

The year 2004 is a leap year. It has 2 odd days.

The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.

Hence, this day is Sunday

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Filed Under: Calendar

139 40728
Q:

Find out the wrong number in the following series:

5, 15, 30, 80, 180, 540, 1080

A) 540 B) 180
C) 30 D) 80
 
Answer & Explanation Answer: D) 80

Explanation:

There should be 90 instead of 80
so we can have a series
5, 5x3, 15x2, 30x3, 90x2, 180x3, 540x2 and 1080x3 and so on...

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Filed Under: Odd Man Out
Exam Prep: Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

6 40548
Q:

 The average age of 8 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is :

A) 20 B) 30
C) 40 D) 50
 
Answer & Explanation Answer: B) 30

Explanation:

Total age increased = (8 * 2) years = 16 years.

Sum of ages of two new men = (21 + 23 + 16) years = 60 years

Average age of two new men = (60/2) years = 30 years.

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Filed Under: Average

86 40527