Quantitative Aptitude - Arithmetic Ability Questions

Q:

What is the value of [(√529) + (√5.29) + (√0.0529)]?

 

A) 25.323   B) 25.53  
C) 23.253   D) 23.53
 
Answer & Explanation Answer: B) 25.53  

Explanation:
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Q:

Odd man out of the series

90 72 56 42 36 20

A) 20 B) 36
C) 42 D) 56
 
Answer & Explanation Answer: B) 36

Explanation:

The given number series is 90 72 56 42 36 20

9 x 10 = 90

8 x 9 = 72

7 x 8 = 56

6 x 7 = 42

5 x 6 = 30 (not 36) 

4 x 5 = 20

 

Hence, the odd man in the given number series is 36.

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Q:

The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

A) 35 B) 36.5
C) 40 D) 42
 
Answer & Explanation Answer: B) 36.5

Explanation:

Correct Sum = (36 * 50 + 48 - 23) = 1825.

Correct mean = = 1825/50 = 36.5

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183 60898
Q:

If sec θ + tan θ = 2, then sec θ - tan θ = ?

 

A) 0.5 B) 1.5
C) 1 D) 0.75
 
Answer & Explanation Answer: A) 0.5

Explanation:
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Q:

Find the odd man out of the number series?

18, 37, 76, 155, 314, 635

A) 37 B) 155
C) 314 D) 635
 
Answer & Explanation Answer: D) 635

Explanation:

Given Number series is 18     37     76     155     314     635

 

follows a pattern that, 

 

18

 

18 x 2 +1 = 37

 

37 x 2 +2 = 76

 

76 x 2 +3 = 155

 

155 x 2 +4 = 314

 

314 x 2 +5 = 633 not 635

 

 

 

Hence, the odd man is 635.

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Q:

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

A) Sunday B) Saturday
C) Tuesday D) Wednesday
 
Answer & Explanation Answer: A) Sunday

Explanation:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005.

So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

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248 60649
Q:

The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is 

A) 10 B) 46
C) 70 D) 90
 
Answer & Explanation Answer: A) 10

Explanation:

Let the numbers be x and (100-x).

 

Then,x100-x=5*495

 

 =>  x2-100x+2475=0

 

 =>  (x-55) (x-45) = 0

 

 =>  x = 55 or x = 45

 

  The numbers are 45 and 55

 

Required difference = (55-45) = 10

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Q:

Find the value of 76413+ 2713314

 

A) 7 B) 6
C) 49 D) 343
 
Answer & Explanation Answer: A) 7

Explanation:
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