Quantitative Aptitude - Arithmetic Ability Questions

Let the C.P of spirit be = Rs.10 per litre

Then S.P l litre of the mixture = Rs. 11

Profit = 20%

Therefore, C.P of the mixture = Rs. 100120×10 = Rs. 25/3 per litre

 Therefore, Ratio of water and spirit = 1 : 5

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R=100*60100*6 =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I=Rs.12000*1+101003-1
       =Rs.3972

For 1st year S.I =C.I.

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

i.e S.I on the principal for 1 year is Rs.200

Principle = Rs.100*2008*1 = Rs.2500

Amount for 2 years, compounded half-yearly

 Rs.2500*1+41004=Rs.2924.4

C.I = Rs.424.64

Also, S.I=Rs.2500*8*2100=Rs.400

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

Let the numbers be x and y.

Then, xy = 9375 and  x/y = 15.

xyxy=9375/15

=>$$\begin{gathered} y2 =625 \\ \end{gathered}$$

=> y = 25

=> x = 15y = 15 x 25 = 375.

Sum of the numbers = 375 + 25 = 400.

We know that 

$$\begin{gathered} 40% = 40100 = 25 \\ ⇒25 x 244 x ? = 48 \\ ? = 48 x 5 x 42 x 24 = 20 \end{gathered}$$

Let , S -  sample space        E - event of selecting 1 girl and 2 boys. 

Then, n(S) = Number ways of selecting 3 students out of 25 

                = 25C3 

                = 2300.

n(E) = 10C1×15C2 = 1050. 

P(E) = n(E)/n(s) = 1050/2300 = 21/46

Next number of the sequence 1, 4, 12, 32,...

1 = 2 x 20

4 = 2 x 21

12 = 3 x 22

32 = 4 x 23

80 = 5 x 24.

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.

But, 8th Dec, 2007 is Saturday

S0, 8th Dec, 2006 is Friday.