Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the next number in the sequence?

28, 16, 28, 76, 274

A) 1233 B) 1243
C) 1256 D) 1276
 
Answer & Explanation Answer: B) 1243

Explanation:

Given number sequence is 28, 16, 28, 76, 274

Here the sequence follows a pattern that

28

28 x 0.5 + 2 = 14 + 2 = 16

16 x 1.5 + 4 = 24 + 4 = 28

28 x 2.5 + 6 = 70 + 6 = 76

76 x 3.5 + 8 = 266 + 8 = 274

274 x 4.5 + 10 = 1233 + 10 = 1243

 

Hence, the next number in the given number sequence is 1243.

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Q:

Which of the following statement(s) is/are TRUE?

 

I . 11×3+13×5+15×7+...+111×13 = 1213

II. 11×2+12×3+13×4+...+112×13 = 1213

A) Only I B) Only II
C) Both I and II D) Neither I nor II
 
Answer & Explanation Answer: B) Only II

Explanation:
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Q:

If S is the midpoint of a straight line PQ and R is a point different from S, such that PR =RQ, then

 

A) ∠PRS = 90° B) ∠QRS = 90°
C) ∠PSR = 90° D) ∠QSR = 90°
 
Answer & Explanation Answer: C) ∠PSR = 90°

Explanation:
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1 61142
Q:

A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used ?

A) 3 months B) 6 months
C) 10 months D) 12 months
 
Answer & Explanation Answer: C) 10 months

Explanation:

Let the total profit be Rs. z. Then,

B's share = Rs. 2z/3,  A's share = Rs. ( z - 2z/3 ) = Rs. z/3.

A : B = z/3 : 2z/3 = 1:2

Let the total capital be Rs, X and suppose B's money was used for x months. Then.

(1(x) / 4 * 15) / (3x) / 4 * y) = 1/2 <=> y = (15 * 2 / 3) = 10 .

 Thus, B's money was used for 10 months.

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125 61106
Q:

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : 

A) 285 B) 290
C) 297 D) 305
 
Answer & Explanation Answer: A) 285

Explanation:

 Since the month begins with a Sunday, so there will be five Sundays in the month,

Required average = (510 * 5 + 240 * 25) / 30 = 8550/30 = 285.

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79 61070
Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only
 
Answer & Explanation Answer: D) Either II or III only

Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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0 61000
Q:

The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

A) 35 B) 36.5
C) 40 D) 42
 
Answer & Explanation Answer: B) 36.5

Explanation:

Correct Sum = (36 * 50 + 48 - 23) = 1825.

Correct mean = = 1825/50 = 36.5

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183 60734
Q:

Given that (a2 + b2) = 60, then find the value of (a + b)2 + (a - b)2 ?

 

A) 90 B) 120
C) 140 D) 150
 
Answer & Explanation Answer: B) 120

Explanation:
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