Quantitative Aptitude - Arithmetic Ability Questions

Q:

The sum of all two digit numbers divisible by 5 is

A) 945 B) 678
C) 439 D) 568
 
Answer & Explanation Answer: A) 945

Explanation:

Required numbers are 10,15,20,25,...,95
This is an A.P. in which a=10,d=5 and l=95.
Let the number of terms in it be n.Then t=95
So a+(n-1)d=95.
10+(n-1)*5=95,then n=18.
Required sum=n/2(a+l)=18/2(10+95)=945.

Report Error

View Answer Report Error Discuss

Filed Under: Numbers

114 42341
Q:

The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 sq.m. The length of the hall is

A) 20 B) 25
C) 30 D) 35
 
Answer & Explanation Answer: C) 30

Explanation:

Let breadth = x m

 

Then, length = (x+5)m

 

Area of a rectangle = Length x Breadth

 

x(x+5) = 750 

 

x² + 5x - 750= 0

 

(x+30)(x-25)= 0

 

x = 25 or x = -30

 

Hence, breadth x = 25m

 

=> Length = x + 5 = 25 + 5 = 30m. 

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

72 42317
Q:

A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be

A) 7744 B) 8844
C) 5544 D) 4444
 
Answer & Explanation Answer: A) 7744

Explanation:

length of wire = 2πr= 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

77 42244
Q:

A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.

A) 136 B) 146
C) 166 D) 176
 
Answer & Explanation Answer: D) 176

Explanation:

area of the room = 544 x 374 sq.cm

size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm

area of 1 tile = 34x34 sq cm

no. of tiles required = (544 x 374) / (34 x 34) = 176

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

62 42088
Q:

Find the ratio of the areas of the incircle and circumcircle of a square.

A) 1:1 B) 1:2
C) 1:3 D) 1:4
 
Answer & Explanation Answer: B) 1:2

Explanation:

Let the side of the square be x. Then, its diagonal = 2x2=2x 

Radius of incircle = x2 

Radius of circum circle= 2×x2=x2 

Required ratio = πx24:πx22=14:12=1:2

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

83 42053
Q:

In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by

A) 21 m B) 26 m
C) 28m D) 29m
 
Answer & Explanation Answer: C) 28m

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Races and Games

40 42041
Q:

How many leap years does 100 years have?

A) 25 B) 24
C) 4 D) 26
 
Answer & Explanation Answer: B) 24

Explanation:

Given year is divided by 4, and the quotient gives the number of leap years.

Here, 100%4 = 25.

But, as 100 is not a leap year => 25 - 1= 24 leap years.

Report Error

View Answer Report Error Discuss

Filed Under: Calendar

139 41996
Q:

Simplify the following equation ?

2003 x 2004 - 2001 x 2002 = ?

A) 8010 B) 8020
C) 8030 D) 8040
 
Answer & Explanation Answer: A) 8010

Explanation:

(2000 + 3)(2000 + 4) - (2000 + 1)(2000 + 2) = ?
Since (2000 x 2000) - (2000 x 2000) is equal to zero. ?
= (8000 + 6000 + 12) - (4000 + 2000 + 2)
=> 14012 - 6002 = 8010.

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

3 41971