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 Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the next number in the given series ?


3, 7, 6, 5, 9, 3, 12, 1, 15, . . .

A) 2 B) 0
C) 1 D) -1
 
Answer & Explanation Answer: D) -1

Explanation:

3, 7, 6, 5, 9, 3, 12, 1, 15, ... has two different series

1) 3, 6, 9, 12, 15.....

2) 7, 5, 3, 1, .....

-1 is the next number.

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Filed Under: Odd Man Out
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3 48870
Q:

At what time between 9 and 10 o'clock will the hands of a watch be together?

A) (49 + 3/11) min past 11 B) (49 +1/11) min past 9
C) (45 +1/11) min past 9 D) (45 +7/11) min past 11
 
Answer & Explanation Answer: B) (49 +1/11) min past 9

Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.
55 min. spaces gained in 60 min.

 

45 min. spaces are gained in 6055×45 min  or 49111min

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Filed Under: Clocks
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64 48868
Q:

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is

A) 4 B) 6
C) 8 D) 12
 
Answer & Explanation Answer: A) 4

Explanation:

Let the required numbers be 33a and 33b. 

 

Then 33a +33b= 528   =>   a+b = 16.

 

Now, co-primes with sum 16 are (1,15) , (3,13) , (5,11) and (7,9).

 

Therefore, Required numbers are  ( 33 x 1, 33 x 15), (33 x 3, 33 x 13), (33 x 5, 33 x 11), (33 x 7, 33 x 9)

 

The number of such pairs is 4

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Filed Under: HCF and LCM

129 48843
Q:

Simplify the following :

4 15 × 3 13 + ? = 20% of 120

A) 10 B) 24
C) 36 D) 40
 
Answer & Explanation Answer: A) 10

Explanation:

Given equation can be written as

215 x 103 + ? = 24=> 14 + ? = 24=> ? = 24 - 14=> ? = 10

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Filed Under: Simplification
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1 48657
Q:

A college has 10 basketball players. A 5-member team and a captain will be selected out of these 10 players. How many different selections can be made?

A) 1260 B) 1400
C) 1250 D) 1600
 
Answer & Explanation Answer: A) 1260

Explanation:

A team of 6 members has to be selected from the 10 players. This can be done in 10C6 or 210 ways. 

Now, the captain can be selected from these 6 players in 6 ways.
Therefore, total ways the selection can be made is 210×6= 1260

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52 48590
Q:

Question :

What is the sum which earned interest ?

Statements :

a. The total simple interest was Rs. 9000 after 9 years.
b. The total of sum and simple interest was double of the sum after 6 years.

A) Only a is sufficient B) Neither a nor b is sufficient
C) Only b is sufficient D) Both a and b sufficient
 
Answer & Explanation Answer: D) Both a and b sufficient

Explanation:

Let the sum be Rs. x

a. gives, S.I = Rs. 9000 and time = 9 years.

b. gives, Sum + S.I for 6 years = 2 x Sum

--> Sum = S.I for 6 years.


Now, S.I for 9 years = Rs. 9000

S.I for 1 year = Rs. 9000/9 = Rs. 1000.

S.I for 6 years = Rs. (1000 x 6)= Rs. 6000.

--> x = Rs. 6000

Thus, both a and b are necessary to answer the question.

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Filed Under: Simple Interest
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5 48508
Q:

The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is 

A) 101 B) 107
C) 111 D) 185
 
Answer & Explanation Answer: C) 111

Explanation:

 Let the numbers be 37a and 37b. Then , 37a x 37b =4107  => ab = 3.

 Now co-primes with product 3 are (1,3)

 So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).

 Therefore, Greater number = 111.

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Filed Under: HCF and LCM

64 48481
Q:

What is 90 days from today?

 

Hints : Today is 20th January 2017, Sunday

A) 18th April, Friday B) 20th April, Saturday
C) 21th April, Sunday D) 19th April, Saturday
 
Answer & Explanation Answer: B) 20th April, Saturday

Explanation:

Given Today is 20th January 2017, Sunday

In january, we have 31 days

February - 28 days (Non leap year)

March - 31 days

April - 30 days

=> Remaining days => 31 - 20 = 11 in Jan

+ 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days

More 20 days to complete 90 days => upto 20th April

 

Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017.

 

Now, the day of the week will be 

90/7 => Remainder '6'

As the day starts with '0' on sunday 

6 => Saturday.

 

Required day is 20th April, Saturday.

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Filed Under: Calendar
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49 48480