6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is

A) 101	B) 107
C) 111	D) 185

Answer & Explanation Answer: C) 111

Explanation:

Let the numbers be 37a and 37b. Then , 37a x 37b =4107 => ab = 3.

Now co-primes with product 3 are (1,3)

So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).

Therefore, Greater number = 111.

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Filed Under: HCF and LCM

64 48070

Q:

Simplify $(2 \sqrt{392} - 21) + {(\sqrt{8} - 7)}^{2} = {(?)}^{2}$

A) 4	B) 5
C) 6	D) 9

Answer & Explanation Answer: C) 6

Explanation:

${(?)}^{2} = (2 \times 7 \sqrt{8} - 21 + 8 + 49 - 14 \sqrt{8}) = 57 - 21 = 36 = > ? = \pm 6$

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

15 47887

Q:

The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs.20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is

A) Rs. 19.50	B) Rs. 19
C) Rs. 18	D) Rs. 18.50

Answer & Explanation Answer: C) Rs. 18

Explanation:

Let the price of the mixed variety be Rs. x per kg. By the rule of alligation, we have :

Cost of 1 kg of type 1 rice Cost of 1 kg of type 2 rice

$∴$ (20-x)/(x-15) = 2/3

$\Rightarrow$ 60 - 3x = 2x - 30

$\Rightarrow$ x = 18.

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Filed Under: Alligation or Mixture

107 47603

Q:

Reena and Shaloo are partners in a business, Reena invests Rs, 35,000 for 8 months and Shaloo invests Rs. 42,000 for 10 months, out of a profit of Rs. 31,570, Reena's share is :

A) 12628	B) 18245
C) 11235	D) 10253

Answer & Explanation Answer: A) 12628

Explanation:

Ratio of their shares = (35000 * 8) : (42000 * 10) = 2 : 3.

Reena's share Rs. 31570 * (2 / 5) = Rs. 12628.

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Filed Under: Partnership

29 47528

Q:

A college has 10 basketball players. A 5-member team and a captain will be selected out of these 10 players. How many different selections can be made?

A) 1260	B) 1400
C) 1250	D) 1600

Answer & Explanation Answer: A) 1260

Explanation:

A team of 6 members has to be selected from the 10 players. This can be done in $10 C_{6}$ or 210 ways.

Now, the captain can be selected from these 6 players in 6 ways.
Therefore, total ways the selection can be made is 210×6= 1260

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Filed Under: Permutations and Combinations

51 47431

Q:

Find compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually.

A) 612	B) 712
C) 812	D) 912

Answer & Explanation Answer: A) 612

Explanation:

Amount = Rs [7500*(1+(4/100)2] = Rs (7500 * (26/25) * (26/25) ) = Rs. 8112.
therefore, C.I. = Rs. (8112 - 7500) = Rs. 612.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

59 47365

Q:

A water tank is two-fifth full.Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes.If both the pipes are open,how long will it take to empty or fill the tank completely?

A) 6 min.to empty	B) 6 min.to fill
C) 9 min.to empty	D) 9 min.to fill

Answer & Explanation Answer: A) 6 min.to empty

Explanation:

Clearly,pipe B is faster than pipe A and so,the tank will be emptied.

part to be emptied = 2/5

part emptied by (A+B) in 1 minute= $(\frac{1}{6} - \frac{1}{10}) = \frac{1}{15}$

$\frac{1}{15} : \frac{2}{5} : : 1 : x$

$\frac{2}{5} * 15 = 6 m i n s$

so, the tank will be emptied in 6 min

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Filed Under: Pipes and Cistern

85 47272

Q:

A basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. If we choose two fruits at random, what is the probability that either both are oranges or both are non defective?

A) 136/345	B) 17/87
C) 316/435	D) 158/435

Answer & Explanation Answer: C) 316/435

Explanation:

$n (s) = {}^{30}C_{2}$

Let A be the event of getting two oranges and

B be the event of getting two non-defective fruits.

and $(A \cap B)$ be the event of getting two non-defective oranges

$∴ P (A) = \frac{{}^{20}C_{2}}{{}^{30}C_{2}}, P (B) = \frac{{}^{22}C_{2}}{{}^{30}C_{2}} a n d P (A \cap B) = \frac{{}^{15}C_{2}}{{}^{30}C_{2}}$

$∴ P (A \cup B) = P (A) + P (B) - P (A \cap B)$

= $\frac{{}^{20}C_{2}}{{}^{30}C_{2}} + \frac{{}^{22}C_{2}}{{}^{30}C_{2}} - \frac{{}^{15}C_{2}}{{}^{30}C_{2}} = \frac{316}{435}$

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Filed Under: Probability

108 46492

Quantitative Aptitude - Arithmetic Ability Questions

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