Quantitative Aptitude - Arithmetic Ability Questions

let length = x and breadth = y then  

2(x+y) = 46         =>   x+y = 23  

x²+y² = 17² = 289  

now (x+y)² = 23² 

=> x²+y²+2xy= 529 

=> 289+ 2xy = 529

=> xy = 120  

area = xy = 120 sq.cm

A's Salary  = 40% of B = 40% of (25% of C) = 40/100[(52/100)*100] % of C = 10% of C.

Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.

Now 23 hrs 44 min. of this clock = 24 hours of correct clock.

356/15 hrs of this clock = 24 hours of correct clock

89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.

= 90 hrs of correct clock.

So, the correct time is 11 p.m.

(x * 5) = (0.75 *8)

X=6/5 = 1.20

$$\begin{gathered} 13 x ? + 47 x 114 x 539 = 31100 x 2000 \\ ? = 378 x 3 \\ ? = 1134 \end{gathered}$$

Let principal = P, Then, S.I.= P and Time = 8 years

We know that S.I. = PTR/100

Rate = [(100 x P)/ (P x 8)]% = 12.5% per annum.

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192

Work done in 6 days=6896+8192=6×18 =34 

Remaining work = 1/4

(8 men +8 women)'s 1 day work = 1896+8192 =1/8

Remaining work =1/4 -  1/8 = 1/8

 1/96 work is done in 1 day by 1 man

Therefore, 1/8 work will be done in 1 day by 96 x (1/8) =12 men