Quantitative Aptitude - Arithmetic Ability Questions

Q:

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

A) Sunday B) Saturday
C) Tuesday D) Wednesday
 
Answer & Explanation Answer: A) Sunday

Explanation:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005.

So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

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Filed Under: Calendar

248 59244
Q:

Find the next number in the given number series?

3, 10.5, 36.75, 128.625, ?

A) 295.651 B) 354.146
C) 398.78 D) 450.187
 
Answer & Explanation Answer: D) 450.187

Explanation:

Here the given number series  3, 10.5, 36.75, 128.625, ? follows a pattern that

3

3 x 3.5 = 10.5

10.5 x 3.5 = 36.75

36.75 x 3.5 = 128.625

128.625 x 3.5 = 450.187

 

Hence the next number in the given number series is 450.187.

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Filed Under: Odd Man Out
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2 59050
Q:

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : 

A) 285 B) 290
C) 297 D) 305
 
Answer & Explanation Answer: A) 285

Explanation:

 Since the month begins with a Sunday, so there will be five Sundays in the month,

Required average = (510 * 5 + 240 * 25) / 30 = 8550/30 = 285.

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Filed Under: Average

79 58704
Q:

A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?

A) 116% B) 166.66%
C) 60% D) 100%
 
Answer & Explanation Answer: B) 166.66%

Explanation:

Let the cost price of 1-liter pure milk be Re.1, then 

 6 liters (milk)   C.P = Rs. 62 liters (water)  C.P = Rs. 0CP = Rs.6 only

 

8 litre mixture  =>

SP =>  8 x 2 = Rs. 16

 

Profit % = 16 - 66x100 = 10006 = 166.66%

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Filed Under: Profit and Loss
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392 58604
Q:

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A) 30 B) 40
C) 50 D) 60
 
Answer & Explanation Answer: A) 30

Explanation:

Let the side of the square(ABCD) be x meters.

 

Then, AB + BC = 2x metres.

 

AC = 2x = (1.41x) m.

 

Saving on 2x metres = (0.59x) m.

 

Saving % =0.59x2x*100 = 30% (approx)

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Filed Under: Area
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96 58572
Q:

In an election only two candidates contested 20% of the voters did not vote and 120 votes were declared as invalid. The winner got 200 votes more than his opponent  thus he secured 41% votes of the total voters on the voter list. Percentage votes of the defeated candidate out of the total votes casted is:

A) 47.5% B) 41%
C) 38% D) 45%
 
Answer & Explanation Answer: D) 45%

Explanation:

Let there be x voters and k votes goes to loser then 

 

      0.8x - 120 = k + (k + 200)

 

         k+200 = 0.41x

 

 => k = 1440

 

and  (k + 200) =1640

 

Therefore  1440/3200 x 100 = 45%

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Filed Under: Percentage

297 58492
Q:

 If log 2 = 0.30103, Find the number of digits in 256 is

A) 17 B) 19
C) 23 D) 25
 
Answer & Explanation Answer: A) 17

Explanation:

log(256) =56*0.30103 =16.85768.

 

Its characteristics is 16.

 

Hence, the number of digits in 256 is 17.

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Filed Under: Logarithms
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119 58425
Q:

If the radius of a circle is decreased by 50%, find the percentage decrease in its area.

A) 55% B) 65%
C) 75% D) 85%
 
Answer & Explanation Answer: C) 75%

Explanation:

Let original radius = R. 

 

New radius = 50100R50100R 

 

Original area =R2  and new area = πR2

 

3πR24*1πR2*100 

 

Decrease in area = πR22=πR24 = 75%

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Filed Under: Area
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147 58418