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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

If 4 (A's capital) = 6 (B's capital) = 10 (C's capital), then out of a profit of Rs. 4650, C will receive ____

A) Rs.700 B) Rs.800
C) Rs.900 D) Rs.1000
 
Answer & Explanation Answer: C) Rs.900

Explanation:

Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6,  and C =k/10 .

 

A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.

 

Hence, C's share (4650 *  6/31) = Rs, 900.

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Filed Under: Partnership

89 65154
Q:

In the following number series, one of the numbers is wrong. Find it out?

77, 79, 76, 81, 75, 85

A) 79 B) 81
C) 75 D) 85
 
Answer & Explanation Answer: C) 75

Explanation:

Here in the given series, it follows a pattern that

 

77 + 2 = 79

 

79  - 3 = 76

 

76 + 5 = 81

 

81 -  7 = 74

 

74 + 11 = 85

 

Consecutive adding and subtracting of prime numbers.

 

So the wrong number in the given series is 75.

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Filed Under: Odd Man Out
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

7 64771
Q:

ΔXYZ is right angled at Y. If sinX = 12/13, then what is the value of cosecZ ?

 

A) 5/12   B)  5/13  
C) 13/5   D)  13/12
 
Answer & Explanation Answer: C) 13/5  

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

0 64591
Q:

What value will come in place of question mark (?) in the number - series given below  ? 

4, 30, ?, 1440, 7195, 71940

A) 145 B) 545
C) 650 D) 999
 
Answer & Explanation Answer: A) 145

Explanation:

4       30       ?     1440       7195      71940

 

Here the given series follows a pattern of

 

4

 

4 x 10 - 10 = 30

 

30 x 5 - 5  = 145

 

145 x 10 - 10 = 1440

 

1440 x 5 - 5 = 7195

 

7195 x 10 - 10 = 71940

 

Hence, the missing number is 145

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Filed Under: Odd Man Out
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

9 64393
Q:

Relation Between Efficiency and Time

A is twice as good a workman as B and is therefore able to finish a piece of work in 30 days less than B.In how many days they can complee the whole work; working together?

Answer

Ratio of times taken by A and B = 1 : 2.


The time difference is (2 - 1) 1 day while B take 2 days and A takes 1 day.


If difference of time is 1 day, B takes 2 days.


If difference of time is 30 days, B takes 2 x 30 = 60 days.


So, A takes 30 days to do the work.


 


A's 1 day's work = 1/30


B's 1 day's work = 1/60


(A + B)'s 1 day's work = 1/30 + 1/60 = 1/20


A and B together can do the work in 20 days.

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Subject: Time and Work

253 64334
Q:

What will be the day of the week 15th August, 2010?

A) Sunday B) Saturday
C) Wednesday D) Monday
 
Answer & Explanation Answer: A) Sunday

Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

 

Odd days in 1600 years = 0

 

Odd days in 400 years = 0

 

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

 

Jan. Feb. Mar.  Apr.  May.  Jun.  Jul.  Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

  

Total number of odd days = (0 + 0 + 4 + 3) = 7 =  0 odd days.

 

Given day is Sunday

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Filed Under: Calendar

522 64285
Q:

Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together ?

A) 100/11 min past 8 B) 120/11 min past 8
C) 90/11 min past 8 D) 80/11 min past 8
 
Answer & Explanation Answer: B) 120/11 min past 8

Explanation:

In this type of problems the formulae is 5x-30×1211
x is replaced by the first interval of given time Here i.e 8
5*8-30*1211
= 12011min

Therefore the hands will be in the same straight line but not
together at 12011 min.past 8.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

101 64277
Q:

A committee of 5 persons is to be formed from 6 men and 4 women. In how many ways can this be done when at least 2 women are included ?

A) 196 B) 186
C) 190 D) 200
 
Answer & Explanation Answer: B) 186

Explanation:

When at least 2 women are included.

 

The committee may consist of 3 women, 2 men : It can be done in  4C3*6C2  ways

 

or, 4 women, 1 man : It can be done in  4C4*6C1ways

 

or, 2 women, 3 men : It can be done in 4C2*6C3 ways.

 

Total number of ways of forming the committees

 

= 4C2*6C3+4C3*6C2+4C4*6C1

 

= 6 x 20 + 4 x 15 + 1x 6

 

= 120 + 60 + 6 =186

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Filed Under: Permutations and Combinations

88 64258