Quantitative Aptitude - Arithmetic Ability Questions

Q:

What will come in place of the question mark (?) in the following question ?

52.5% of 800 + 30.5% of 2800 = ? + 87.30

A) 1096.30 B) 1226.70
C) 1124.20 D) 1186.70
 
Answer & Explanation Answer: D) 1186.70

Explanation:

52.5% of 800 + 30.5% of 2800 = ? + 87.30

420 + 854 - 87.30 = ?

1274 - 87.30 = ?

? = 1186.70

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Filed Under: Percentage
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10 60318
Q:

The radius of base of a right circular cone is 6cm and its slant height is 10cm. Then its volume is

(use π=227)

A) 301.71 cm3 B) 310.71 cm3
C) 301.17 cm3 D) 310.17 cm3
 
Answer & Explanation Answer: A) 301.71 cm3

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 60317
Q:

Gaurav spends 30% of his monthly income on food articles, 40% of the remaining on conveyance and clothes and saves 50% of the remaining. If his monthly salary is Rs. 18,400, how much money does he save every month ?

A) 3864 B) 4903
C) 5849 D) 6789
 
Answer & Explanation Answer: A) 3864

Explanation:

Saving  = 50% of (100 - 40)% of (100 - 30)% of Rs. 18,400 = Rs. (50/100 * 60/100 * 70/100 * 18400) = Rs. 3864.

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Filed Under: Percentage

282 60210
Q:

Find the Odd One Out?

4, 6, 12, 30, 81, 315.

A) 6 B) 12
C) 81 D) 315
 
Answer & Explanation Answer: C) 81

Explanation:

Given the number series is 4, 6, 12, 30, 81, 315.

Here it follows a pattern that

4

4 x 1.5 = 6

6 x 2 = 12

12 x 2.5 = 30

30 x 3 = 90 not equals to 81

90 x 3.5 = 315

 

Hence the odd one in the series is 81.

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9 59995
Q:

(51 + 52 + 53 + .........+100) is equal to

Answer

51 + 52 + 53 + ...........+ 100


 = (1 + 2 + 3 + .... + 100) - (1 + 2 + 3 + ...... + 50)


 = It is in the form of n(n+1)2 series summation


= n1 = 100 , n2 = 50


=100100+12 - 5050+12


 =  (5050 - 1275) = 3775

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Subject: Numbers Exam Prep: AIEEE , Bank Exams , CAT
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300 59923
Q:

What will come in place of the question mark (?) in the following number series?

5, 7, ?, 25, 45, 75

A) 11 B) 13
C) 15 D) 19
 
Answer & Explanation Answer: B) 13

Explanation:

The series given follow the pattern

 

+2, +2+4, +2+4+6, +2+4+6+8, +2+4+6+8+10,...

 

Here ? = 7 + 2 + 4 = 13.

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Filed Under: Odd Man Out
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10 59784
Q:

What is the age of Teja?

A: Four years ago, Raju was as old as Teja is at present.

B: Sita’s present age is two times of Raju’s present age.

C: The average age of Teja and Sita is 19 years.

A) Any two statements are sufficient to give answer B) Only C is sufficient
C) All of three statements are necessary to give answer D) Even using all the three statements answer cannot be found
 
Answer & Explanation Answer: C) All of three statements are necessary to give answer

Explanation:

From the given statements A, B & C

Let the present age of Teja = P

Raju present age = P + 4

Sita's present age = 2(P + 4)

Average of ages of Sita & Teja = 19

=> (2P + 8 + P)/2 = 19

= 3P + 8 = 38

=> P = 30/3 = 10

Hence, the present age of Teja = P = 10 yrs.

 

Therefore, by using all the three statements A, B & C we can find the age of Teja.

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Filed Under: Problems on Ages
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14 59567
Q:

The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is 

A) 10 B) 46
C) 70 D) 90
 
Answer & Explanation Answer: A) 10

Explanation:

Let the numbers be x and (100-x).

 

Then,x100-x=5*495

 

 =>  x2-100x+2475=0

 

 =>  (x-55) (x-45) = 0

 

 =>  x = 55 or x = 45

 

  The numbers are 45 and 55

 

Required difference = (55-45) = 10

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Filed Under: HCF and LCM

151 59457