6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 130 marks, the no of questions he attempts correctly is :

A) 35	B) 38
C) 40	D) 42

Answer & Explanation Answer: B) 38

Explanation:

Let the number of correct answers be X.

Number of incorrect answers = (60 – X).

4x – (60 – x) = 130

=> 5x = 190

=> x = 38

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Filed Under: Simplification

265 87638

Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:

A) 5.4m	B) 4.5m
C) 5m	D) 6m

Answer & Explanation Answer: D) 6m

Explanation:

A : B = 100 : 90.

A : C = 100 : 87.

B/C = (B/A*A/C) = (90/100*100/87) = 30/29

When B runs 30 m, C runs 29 m.

When B runs 180 m, C runs (29/30*180)m =174m

B beats C by (180 - 174) m = 6 m.

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Filed Under: Races and Games

104 87390

Q:

Find the next number in te given series ?

5, 25, 61, 113, ...

A) 142	B) 181
C) 156	D) 179

Answer & Explanation Answer: B) 181

Explanation:

Here the series follow the rule that

$1^{2} + 2^{2} = 5$

$3^{2} + 4^{2} = 25$

$5^{2} + 6^{2} = 61$

$7^{2} + 8^{2} = 113$

SO NEXT IS, $9^{2} + 10^{2} = 181$

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Filed Under: Odd Man Out
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

13 86906

Q:

If each edge of a cube is increased by 50%, find the percentage increase in Its surface area

A) 125%	B) 150%
C) 175%	D) 110%

Answer & Explanation Answer: A) 125%

Explanation:

Let the edge = a cm

So increase by 50 % = a + a/2 = 3a/2

Total surface Area of original cube = $6 a^{2}$

TSA of new cube = $6 {(\frac{3 a}{2})}^{2}$ = $6 (\frac{9 a^{2}}{4})$ = $13.5 a^{2}$

Increase in area = $13.5 a^{2} - 6 a^{2}$ = $7.5 a^{2}$

$7.5 a^{2}$ Increase % = $\frac{7.5 a^{2}}{6 a^{2}} \times 100$ = 125%

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Filed Under: Volume and Surface Area

483 86599

Q:

Find the odd number out of the following number series?

2 4 8 11.5 18.25 28.375

A) 18.25	B) 28.375
C) 11.5	D) 8

Answer & Explanation Answer: D) 8

Explanation:

Given number series follows a pattern that,

2

2 x 1.5 + 1 = 4

4 x 1.5 + 1 = 7 (not equal to 8)

7 x 1.5 + 1 = 11.5

11.5 x 1.5 + 1 = 18.25

18.25 x 1.5 + 1 = 28.375

Hence, the odd number in the given number series is 8.

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Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

17 86407

Q:

What is the rate of interest p.c.p.a.?

I. An amount doubles itself in 5 years on simple interest.

II. Difference between the compound interest and the simple interest earned on a certain amount in 2 years is Rs. 400.

III. Simple interest earned per annum is Rs. 2000

A) I only	B) II and III only
C) All I, II and III	D) I only or II and III only

Answer & Explanation Answer: D) I only or II and III only

Explanation:

$I . \frac{P * R * 5}{100} = P \Leftrightarrow R = 20$

$I I . P {(1 + \frac{R}{100})}^{2} - P - \frac{P * R * 2}{100} = 400 = > p R^{2} = 4000000$

$I I I . \frac{P * R * 1}{100} = 2000 = > P R = 200000$

$\frac{P R^{2}}{P R} = \frac{4000000}{200000} \Leftrightarrow R = 20$

Thus I only or (II and III) give answer.

Correct answer is (D)

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

94 86290

Q:

A, B, C started a business with their investments in the ratio 1:3 :5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments. The ratio of their profits at the end of the year is :

A) 1 : 2 : 3	B) 3 : 4 : 15
C) 3 : 5 : 10	D) 5 : 6 : 10

Answer & Explanation Answer: D) 5 : 6 : 10

Explanation:

Let their initial investments be x, 3x and 5x respectively. Then,

A:B:C = (x*4+2x*8) : (3x*4+(3x/2)*8) : (5x*4+(5x/2)*8)

20x : 24x : 40x = 5 : 6 : 10

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Filed Under: Partnership

207 85364

Q:

What was the day of the week on 28th May, 2006?

A) Sunday	B) Friday
C) Wednesday	D) Tuesday

Answer & Explanation Answer: A) Sunday

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days

(31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd days.

Given day is Sunday

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Filed Under: Calendar

521 84545

Quantitative Aptitude - Arithmetic Ability Questions

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