5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

A certain sum is invested for 2 years in scheme M at 20% p.a. compound interest (compounded annually), Same sum is also invested for the same period in scheme N at k% p.a. simple interest. The interest earned from scheme M is twice of that earned from scheme N. What is the value of k?

A) 7	B) 11
C) 9	D) 13

Answer & Explanation Answer: B) 11

Explanation:

Interest earned in scheme M =

$P [{(1 + \frac{20}{100})}^{2} - 1] = \frac{11 P}{25}$

Interest earned in scheme N =

$\frac{P x k x 2}{100} = \frac{P k}{50}$

Now, from the given data,

$\frac{11 P}{25} = 2 x \frac{P k}{50}$

k = 11

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Filed Under: Compound Interest
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Q:

In a certain code language, "MATERIAL" is written as "RIALMATE". How is "REMEMBER" written in that code language?

A) REMEREBM	B) MBEREMER
C) MBERREME	D) MBERREEM

Answer & Explanation Answer: C) MBERREME

Explanation:

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Filed Under: Coding and Decoding
Exam Prep: Bank Exams

2 4127

Q:

The sum of the two digits of a number is 8. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number ?

A) 28	B) 19
C) 37	D) 17

Answer & Explanation Answer: D) 17

Explanation:

Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 8 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 1 and Q = 7
The required number is = 17

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Filed Under: Problems on Numbers
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1 4123

Q:

What is the interest rate per annum, if a sum of money invested at compound interest amount to Rs. 2400 in 3 years and in 4 years to Rs. 2,520?

A) 3.5%	B) 4%
C) 5%	D) 6.5%

Answer & Explanation Answer: C) 5%

Explanation:

Let 'R%' be the rate of interest

From the given data,

$\frac{2520}{2400} = \frac{{(1 + \frac{R}{100})}^{4}}{{(1 + \frac{R}{100})}^{3}} \Rightarrow (1 + \frac{R}{100}) = \frac{63}{60} \Rightarrow R = 5$

Hence, the rate of interest R = 5% per annum.

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Filed Under: Compound Interest
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19 4121

Q:

In a city of engineers of 4800, the number of female engineers are 3/8th of them. The number of female engineers is what percentage of the number of male engineers?

A) 76	B) 60
C) 56	D) 52

Answer & Explanation Answer: B) 60

Explanation:

Total engineers = 4800

Number of female engineers = 3/8 x 4800 = 1800

Then, number of male engineers = 4800 - 1800 = 3000

Now, required is female engineers is what percentage of the number of male engineers

=> 1800 is what % of 3000

=> p x 3000/100 = 1800

=> 30p = 1800

p = 60%

Hence, female engineers is 60 percentage of the number of male engineers.

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Filed Under: Percentage
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6 4120

Q:

A, B and C together can finish a task in 12 days. A is twice as productive as B and C alone can do the task in 36 days. In how many days can A and B do the task if C goes on leave?

A) 10	B) 20
C) 15	D) 18

Answer & Explanation Answer: D) 18

Explanation:

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Filed Under: Time and Work
Exam Prep: Bank Exams

3 4116

Q:

A bike runs at the speed of 35 km/h when not serviced and runs at 55 km/h, when serviced. After servicing the bike covers a certain distance in 5 h. How much approximate time will the bike take to cover the same distance when not serviced?

A) 8 hrs	B) 7.5 hrs
C) 7 hrs	D) 6.5 hrs

Answer & Explanation Answer: A) 8 hrs

Explanation:

Given speed of the bike after servicing = 55 kmph

Time taken for travelling some distance at 55 kmph = 5 hrs

Then,

Distance = Speed x Time = 55 x 5 = 275 kms.

Now,

Speed of the bike before servicing = 35 kmph

Distance = 275 kms

Now, Time = Distance/Speed = 275/35 = 7.85 hrs =~ 8 hrs.

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Filed Under: Time and Distance
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9 4116

Q:

Find the average of first 50 natural numbers?

A) 25	B) 25.5
C) 26	D) 26.5

Answer & Explanation Answer: B) 25.5

Explanation:

We Know that sum of the n natural numbers = $\frac{n (n + 1)}{2}$

Then sum of 50 natural numbers= $\frac{50 (51)}{2}$ = 1250

Average of the 50 natural numbers = $\frac{1250}{50}$ = 25.5

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Filed Under: Average
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Aptitude and Reasoning Questions

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

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Verbal Reasoning - Logical Deduction

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