Aptitude and Reasoning Questions

Let S be the sample space and E be the event of selecting 1 girl and 2 boys.

Then, n(S) = Number ways of selecting 3 students out of 25

                = 25C3  = 2300.

         n(E)= 10C1*15C2 = 1050. 

P(E) = n(E)/n(s) = 1050/2300 = 21/46

A straight line segment whose endpoints both lie on the circle is called as chord. A chord that passes through the center of a circle is a diameter.

We know that, to be in the form that the number of rows and the number of columns to be equal the number should be a perfect square (a2).

Given number is 1200

The perfect number which is above and near to 1200 is 1225 which is 35  35.

Therefore, The minimum number of coins he need is 25. 

Let the number of students = 100

Number of students who failed in one or more subjects = 14 + 22 + 18 = 54%

The percentage of students who passed in both the subjects = 100 - 54 = 46%.

The simplest triangles are AFJ, FJK, FKB, BKG, JKG, JGC, HJC, HIJ, DIH, DEI, EIJ and AEJ i.e. 12 in number.

The triangles composed of two components each are JFB, FBG, BJG, JFG, DEJ, EJH, DJH and DEH i.e. 8 in number.

The triangles composed of three components each are AJB, JBC, DJC and ADJ i.e. 4 in number.

The triangles composed of six components each are DAB, ABC, BCD and ADC i.e. 4 in number.

Thus, there are 12 + 8 + 4 + 4 = 28 triangles in the figure.

We have P = 15 000, r = 0.07 and since the actual date the loan was taken out
is not given, we use t =7/12

I = Prt=$15 000* 0.07* 7/12 = $612.50

Amount repaid = Future or accumulated value,

S = P + I = $15 000 + $612.50 = $15 612.50

I = (p x t x r)/100