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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Find the missing alphabet in the given sequence ?

A, Z, Y, B, C, ?, W, D

A) E B) Z
C) X D) F
 
Answer & Explanation Answer: C) X

Explanation:

first letter A with last letter Z
similarly 2nd last letter Y with 2nd letter B
Now 3rd letter C with 3rd last letter X
4th last letter W with 4th letter D
and so on....

Therefore the missing letter is X

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Filed Under: Alphabet Test
Exam Prep: AIEEE , Bank Exams
Job Role: Bank PO

35 111698
Q:

LAP  BUT  CAR  SON  HID

 

If the positions of the first and the third alphabets of each of the words are interchanged, which of the following would form a meaningful word in the new arrangement?

A) HID B) SON
C) Both LAP and BUT D) Both CAR and LAP
 
Answer & Explanation Answer: C) Both LAP and BUT

Explanation:

When positions of first and the third alphabets of each of the words are interchanged, we have PAL  TUB  RAC  NOS  DIH

Clearly, PAL and TUB are the only meaningful words. These words are obtained from LAP and BUT respectively. 

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Filed Under: Alphabet Test

227 111210
Q:

Salaries of Ravi and Sumit are in the ratio 2:3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40:57. What is Sumit's salary?

A) 38000 B) 46800
C) 36700 D) 50000
 
Answer & Explanation Answer: A) 38000

Explanation:

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then,
(2x+4000) / (3x+4000) = 40 / 57
⇒ 57 × (2x + 4000) = 40 × (3x+4000)
⇒ 6x = 68,000
⇒ 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000

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Filed Under: Ratios and Proportions

431 110434
Q:

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

If the first five letters of English alphabet are reversed , so are the next five and so on and last letter is left unchanged then what will be 2nd letter to the left of 17th letter from the right?

A) S B) G
C) H D) R
 
Answer & Explanation Answer: C) H

Explanation:

2nd letter to the left of 17th letter from the right means (2 + 17 = ) 19th letter from the right = (26 - 19 + 1 =) 8th letter from the left end , i.e H.  Thus, 8th letter falls into the second section of the reversed sequence. Now, the sequence FGHIJ is reversed and becomes JIHGF. Clearly, position of H remains unchanged. Hence the required letter is H.

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Filed Under: Alphabet Test

22 109417
Q:

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

A) 2/91 B) 1/22
C) 3/22 D) 2/77
 
Answer & Explanation Answer: A) 2/91

Explanation:

Let S be the sample space.

Then, n(S) = number of ways of drawing 3 balls out of 15 = 15C3  =15*14*133*2*1= 455.  

Let E = event of getting all the 3 red balls.

 n(E) = 5C3 = 5*42*1 = 10.

 => P(E) = n(E)/n(S) = 10/455 = 2/91.

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Filed Under: Probability

201 109075
Q:

Simplify  

1.53 + 4.73 + 3.83 - 3 x 1.5 x 4.7 x 3.81.52 + 4.72 + 3.82 - 1.5 x 4.7 - 4.7 x 3.8 - 1.5 x 3.8

A) 6 B) 8
C) 10 D) 12
 
Answer & Explanation Answer: C) 10

Explanation:

Apply a3 + b3 + c3 - 3abca2 + b2 + c2 - ab - bc - ca = a + b + c

 

Hence the answer is  1.5 + 4.7 + 3.8 = 10.

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

34 109001
Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A) Monday B) Friday
C) Sunday D) Tuesday
 
Answer & Explanation Answer: B) Friday

Explanation:

On 31st December, 2005 it was Saturday. 

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. 

 

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

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Filed Under: Calendar

683 108200
Q:

A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was :

A) 14 B) 19
C) 33 D) 38
 
Answer & Explanation Answer: A) 14

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19. 

 

Son's age 5 years back = (19 - 5) = 14 years

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Filed Under: Problems on Ages

525 107913