5555+ Aptitude and Reasoning Questions, Answers With Explanation

Q:

Select a suitable figure from the four alternatives that would complete the figure matrix.

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: C) 3

Explanation:

In each column, the second figure (middle figure) is obtained by removing the upper part of the first figure (uppermost figure) and the third figure (lowermost figure) is obtained by vertically inverting the upper part of the first figure.

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Filed Under: Figure Matrix

51 5208

Q:

What is the value of cosec 120°

A) 2/√3	B) 2
C) -2/√3	D) -2

Answer & Explanation Answer: A) 2/√3

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

7 5206

Q:

There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number?

A) 29	B) 27
C) 31	D) 33

Answer & Explanation Answer: A) 29

Explanation:

Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4

According to the question,

Difference between square of the average of first two odd number and the of the average last

two odd numbers is 396

i.e, x+3 and x-3

$\Rightarrow {(x + 3)}^{2} - {(x - 3)}^{2} = 396 \Rightarrow x^{2} + 9 + 6 x - x^{2} + 6 x - 9 = 396 \Rightarrow 12 x = 396 \Rightarrow x = 33$

Hence, the smallest odd number is 33 - 4 = 29.

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Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

4 5198

Q:

A standard deck of playing cards has 13 spades. How many ways can these 13 spades be arranged?

A) 13!	B) 13^2
C) 13^13	D) 2!

Answer & Explanation Answer: A) 13!

Explanation:

The solution to this problem involves calculating a factorial. Since we want to know how 13 cards can be arranged, we need to compute the value for 13 factorial.

13! = (1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13) = 6,227,020,800

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Filed Under: Permutations and Combinations

2 5196

Q:

If (1 / 2.315) = 0.4319, find the value of (1 / 0.0002315).

A) 4319	B) 2315
C) 431.9	D) 231.5

Answer & Explanation Answer: A) 4319

Explanation:

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Filed Under: Decimal Fractions
Exam Prep: Bank Exams

2 5195

Q:

Find the compound interest on Rs. 6,500 for 4 years if the rate of interest is 10% p.a. for the first 2 years and 20% per annum for the next 2 years?

A) Rs. 3845	B) Rs. 4826
C) Rs. 5142	D) Rs. 4415

Answer & Explanation Answer: B) Rs. 4826

Explanation:

We know the formula for calculating

The compound interest $C = P [{(1 + \frac{r}{100})}^{n} - 1]$ where P = amount, r = rate of interest, n = time

Here P = 5000, r1 = 10, r2 = 20

Then $C = 6500 [{(1 + \frac{10}{100})}^{2} x {(1 + \frac{20}{100})}^{2} - 1] = 6500 x \frac{1856}{2500} = \frac{65 x 1856}{25}$

C = Rs. 4826.

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Filed Under: Compound Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , Database Administration , IT Trainer

20 5195

Q:

What is the difference between the compound interests on Rs. 5000 for $1 \frac{1}{2}$ years at 4% per annum compounded yearly and half-yearly?

A) Rs.3.06	B) Rs.2.04
C) Rs.3.65	D) Rs.5.40

Answer & Explanation Answer: B) Rs.2.04

Explanation:

C.I. when interest compounded yearly

$R s . [5000 * (1 + \frac{4}{100}) * (1 + \frac{\frac{1}{2} * 4}{100})]$

$R s . [5000 * \frac{26}{25} * \frac{51}{50}]$

=Rs.5034

C.I. when interest iscompounded half-yearly

$R s . [5000 * {(1 + \frac{2}{100})}^{3}]$

= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 5194

Q:

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by

A) 5.4 m	B) 4.5 m
C) 5 m	D) 6 m

Aptitude and Reasoning Questions

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Non Verbal Reasoning

Quantitative Aptitude - Arithmetic Ability

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Verbal Reasoning - Logical Deduction

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