Aptitude and Reasoning Questions

Q:

Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ?

A) 108 B) 107
C) 109 D) 110
 
Answer & Explanation Answer: C) 109

Explanation:

From given data,

R : M = 5 : 7

M : A = 5 : 7

R : M : A = 25 : 35 : 49

25 + 35 + 49 = 109

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Filed Under: Ratios and Proportions
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Q:

The ratio of the speeds of a car, a jeeps and a tractor is 3 : 5 : 2. The speed of the jeep is 250 per cent of the speed of the tractor and tractor covers 360 km in 12 hours. What is the average speed of car and jeep together?

A) 50 kmph B) 60 kmph
C) 70 kmph D) 80 kmph
 
Answer & Explanation Answer: B) 60 kmph

Explanation:

Speed of tractor = 360/12 = 30 kmph

Speed of jeep = 250 x 30/100 = 75 kmph

But, given ratio of speed of car, jeep and tractor is 3 : 5 : 2

Speed of car = 3 x 75/5 = 45 kmph

 

Required, average speed of car and jeep = 75 + 45/2 = 60 kmph.

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Filed Under: Time and Distance
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Q:

A train travelling at 48 kmph crosses another train, having half its length and travelling in opposite direction at 42 kmph, in 12 sec. It also covers a bridge in 45 sec. Find the length of the bridge ?

A) 250 mts B) 400 mts
C) 320 mts D) 390 mts
 
Answer & Explanation Answer: B) 400 mts

Explanation:

Let the length of the 1st train = L mts

Speed of 1st train = 48 kmph

Now the length of the 2nd train = L/2 mts

Speed of 2nd train = 42 kmph

Let the length of the bridge = D mts

Distance = L + L/2 = 3L/2

Relative speed = 48 + 42 = 90 kmph = 90 x 5/18 = 25 m/s(opposite)

Time = 12 sec

=> 3L/2x25 = 12

=> L = 200 mts

Now it covers the bridge in 45 sec

=> distance = D + 200

Time = 45 sec

Speed = 48 x5/18 = 40/3 m/s

=> D + 200/(40/3) = 45

=> D = 600 - 200 = 400 mts

Hence, the length of the bridge = 400 mts.

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Filed Under: Problems on Trains
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Q:

When John arrives in New York,he has eight stops to see, but he has time only to visit six of them.In how many different ways can he arrange his schedule in New York?

A) 20610 B) 24000
C) 20160 D) 21000
 
Answer & Explanation Answer: C) 20160

Explanation:

He can arrange his schedule in 8P6 = 20160 ways

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Q:

Present ages of Deepa and Hyma are in the ratio of 5:6 respectively. After four years, this ratio becomes 6: 7. What is the difference between their present ages?

A) 6 yrs B) 4 yrs
C) 8 yrs D) 2 yrs
 
Answer & Explanation Answer: B) 4 yrs

Explanation:

Let the present age of Deepa = 5p

Let the present age of Hyma = 6p

After four years their ratio = 6 : 7

=> 5p + 46p + 4 = 67

=> 35p + 28 = 36p + 24

=> p = 4

Therefore, the difference between their ages = 24 - 20 = 4 years.

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Filed Under: Problems on Ages
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Q:

Find value of log27 +log 8 +log1000log 120

A) 1/2 B) 3/2
C) 2 D) 2/3
 
Answer & Explanation Answer: B) 3/2

Explanation:

 = log 33 + log 23+ log 103log10×3×22 

 

 

 

=log33 12+log 23+log 10312log(10×3×22)  

 

 

 

 

 

 

 

=12log 33+3 log 2+12 log103log10+log3+log22  

 

 

 

 

 

 

 

=32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32  

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Filed Under: Logarithms
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27 5277
Q:

B3D means B is the father of D.
B7D means B is the sister of D.
B2D means B is the brother of D.
B1D means B is the wife of D.

Which of the following means F is the mother of K?

A) F3M1K B) F9M4N3K
C) K3M4N5F D) F1M3K
 
Answer & Explanation Answer: D) F1M3K

Explanation:

From the given information,

F1M → F is the wife of M
M3K → M is the father of K
Therefore, F is the mother of K.

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Filed Under: Blood Relations
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Q:

From a deck of 52 cards, a 5 card hand is dealt.How may distinct five card hands are there if the queen of spades and the four of diamonds must be in the hand?

A) 52C5 B) 50C3
C) 52C4 D) 50C4
 
Answer & Explanation Answer: B) 50C3

Explanation:

If the queen of spades and the four of diamonds must be in hand,we have 50 cards remaining out of which we are choosing 3.

 

So, 50C3

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