Aptitude and Reasoning Questions

Let Ishika and her daughter present ages be p and q

 From the given data, 

p = 4/3(p - 9)

 => p = 36 years 

Hence, Ishika's present age = 36 years and

Her daughter's present age = 1/6 x 36 = 6 years 

Now, required her daughter’s age three years ago = 6 - 3 = 3 years.

We know that,

Area of rectangle A = L x W = 5 x 3 = 15 sq.inches.

Justification:      

In the first and second statements, the common code digit is '8' and the commmon word is 'good'.

So, '8' means 'good'.
In the first and third statements, the common code digit is '1' and the common word is 'fruit'.
So, '1' means 'fruit'.
Thus, in the first statement, '5' means 'sweet'.

Let the daughter age be 'x'
Therefore, Son age = 5x, Mother age = 25x, Person age = 50x.

Thus we get, x+5x+25x+50x = 81
81x = 81
x = 1

Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.

Here, s={H,T} and E={H}
P(E) = n(E)/n(S) = 1/2

Cash price = $21 000

Deposit = 10% × $21 000 = $2100 

Loan amount = $21000 − $2100 = $18900

I=p x r x t/100 

I=11340

Total amount = 18900 + 11340 = $30240

Regular payment = total amount /number of payments

Given principal amount = Rs. 8000

Time = 3yrs

Rate = 5%

C.I for 3 yrs = $$\begin{gathered} 8000 x 105100 x 105100 x 105100 - 8000 \\ = Rs. 1261 \end{gathered}$$

Now, C.I for 2 yrs = $$\begin{gathered} 8000 x 105100 x 105100 \\ = Rs. 820 \end{gathered}$$

Hence, the required difference in C.I is 1261 - 820 = Rs. 441

Let the numbers be x, x+1, x+2 

Then x + x+1 + x+2 = 42

           =>  3x + 3 = 42

           => 3x = 39 

          =>  x = 13

The numbers would be 13, 14, 15 

Therefore, Sum of the digits of middle number = 1+4 = 5