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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

STIMULANT : ACTIVITY ::

A) diagnosis : treatment B) fertilizer : growth
C) symptom : disease D) food : hunger
 
Answer & Explanation Answer: B) fertilizer : growth

Explanation:
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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , GRE , TOEFL
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14 6471
Q:

A school has scheduled three volleyball games, two soccer games, and four basketball games. You have a ticket allowing you to attend three of the games. In how many ways can you go to two basketball games and one of the other events?

A) 25 B) 30
C) 50 D) 75
 
Answer & Explanation Answer: B) 30

Explanation:

Since order does not matter it is a combination. 

 

The word AND means multiply. 

 

Given 4 basketball, 3 volleyball, 2 soccer. 

 

We want 2 basketball games and 1 other event. There are 5 choices left. 

C(n,r) 

C(How many do you have, How many do you want) 

C(have 4 basketball, want 2 basketball) x C(have 5 choices left, want 1) 

C(4,2) x C(5,1) = (6)(5) = 30

 

Therefore there are 30 different ways in which you can go to two basketball games and one of the other events.

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Filed Under: Permutations and Combinations

1 6471
Q:

Jeopardy : Peril :: Jealousy : ?

A) Lust B) Sin
C) Envy D) Insecurity
 
Answer & Explanation Answer: C) Envy

Explanation:

First is a more intense form of the second. Here Jeopardy is the more intense form of Peril and we know that Jealousy is the more intense form of Envy.

 

Hence, Jeopardy : Peril :: Jealousy : Envy.

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

5 6469
Q:

Identify the diagram that best represents the relationship among the given classes.

 

Stationery, Pencil, Rubber

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: D) 4

Explanation:
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Filed Under: Logical Venn Diagram
Exam Prep: Bank Exams

1 6466
Q:

A can do a work in 9 days, B can do a work in 7 days, C can do a work in 5 days. A works on the first day, B works on the second day and C on the third day respectively that is they work on alternate days. When will they finish the work ?

A) [7 + (215/345)] days B) [6 + (11/215)] days
C) [6 + (261/315)] days D) [5 + (112/351)] days
 
Answer & Explanation Answer: C) [6 + (261/315)] days

Explanation:

After day 1, A finishes 1/9 of the work.

After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished.

After day 3, C finishes 1/5 more of total work. Total finished is 143/315.

So, after day 6, total work finished is 286/315.

 

Now remaining work =  29 /315

 

On day 7, A will work again 

 

Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.

 

Since he takes 9 days to finish the total task, he will need 261/315 of the day. 

 

Total days required is 6 + (261/315) days.

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Filed Under: Time and Work
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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6 6464
Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years 


Then B's age 10 years ago  be 2x yeats


\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}


\inline \Rightarrow 4(x+10)=3(2x+10)


\inline \Rightarrow x=5


\inline \therefore Total of their present ages =                                        


                                          = 


                                          = 35 years

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Subject: Problems on Ages

9 6464
Q:

At an examination in which maximum marks are 500. K got 10% less than L, L got 25% more than M and M got 20% less than N. If K got 360 marks what percentage of marks was obtained by N ?

A) 80 B) 87
C) 78 D) 76
 
Answer & Explanation Answer: A) 80

Explanation:

Let marks obtained by N = x

M's marks = 0.80x

L's marks = 1.25 (0.80x)

K's marks = (0.90) (1.25) (0.80x)

= 0.9x

But 0.9x = 360 ⇒ x = 400

Percentage of Marks obtained by N

= 400 x 100/500 = 80%

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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7 6463
Q:

When Dr. Ram arrives in his dispensary, he finds 12 patients waiting to see him. If he can see only one patients at a time,find the number of ways, he can schedule his patients if 3 leave in disgust before Dr. Ram gets around to seeing them.

A) 479001600 B) 79833600
C) 34879012 D) 67800983
 
Answer & Explanation Answer: B) 79833600

Explanation:

There are 12 - 3 = 9 patients.They can be seen in 12P9 = 79833600 ways

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Filed Under: Permutations and Combinations

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