Aptitude and Reasoning Questions

All males are Human beings so the circle for male come in between human being; and all fathers are male so the circle for fathers comes in between the male circle. So, option C suits best.

Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4

Let number of 20 ps coins = x and

number of 25 ps coins = y

Given total coins in the bag = 50

x + y = 50.......(1)

But the total money in the bag = Rs. 10.25

0.20x + 0.25y = 10.25

20x + 25y = 1025.........(2)

Now multiplying (1) by 25 we get

25x+25y=1250.............(3)

By solving (2) and (3)

20x + 25y = 1025;

=> x = 45;

Then, the no. of 20 ps coins are 45.

The given series when written in reverse order becomes:

13, 11, 5, 0, 1, 2, 6, 4, 8, 3, 0, 7, 9, 3, 7

The seventh number from the left is 6, the fourth number to the right of 6 is 0

Let the length of the brigade is x mts
Then Distance = 130 + x mts
given speed = 45 kmph = 45 x5/18 m/s
Time = 30 sec
T = D/S
=> 30 = 130+x/(45x5/18)
=> x = 245 mts.

Probability of left handed = 4/5
total student = 40
total left handed = 40 x(4/5)
= 32

Work done by Shyam and Rahim in 8 days = 8/32 = 1/4

Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4

Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days.

One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96

Hence, the total work can be done by Shyam and Ram together in 96/5 days.

Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.

Let the lent at 5% be 'A'

(A x 5 x 1)/100 + [(1500 - A)x 6 x 1]/100 = 85

5A/100 + 90 – 6A/100 = 85

A/100 = 5

=> A = 500