Aptitude and Reasoning Questions

Q:

When six fairs coins are tossed simultaneously, in how many of the outcomes will at most three of the coins turn up as heads ?

A) 15 B) 42
C) 16 D) 40
 
Answer & Explanation Answer: B) 42

Explanation:

The question requires you to find number of the outcomes in which at most 3 coins turn up as heads.

i.e., 0 coins turn heads or 1 coin turns head or 2 coins turn heads or 3 coins turn heads.

 

The number of outcomes in which 0 coins turn heads is 6C0=1 

The number of outcomes in which 1 coin turns head is =6C1=6 

The number of outcomes in which 2 coins turn heads is6C2=15 

The number of outcomes in which 3 coins turn heads is6C3=20

 

Therefore, total number of outcomes =1+6+15+20= 42 outcomes

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Q:

An electronic device when fed with the numbers, rearranges them in a particular order following certain rules. The following is a step-by-step process of rearrangement for the given input of numbers.

 

Input    :- 85   16   36   04   19   97   63   09

Step I   :- 97   85   16   36   04   19   63   09

Step II  :- 97   85   63   16   36   04   19   09

Step III :- 97   85   63   36   16   04   19   09

Step IV :- 97   85   63   36   19   16   04   09

Step V  :- 97   85   63   36   19   16   09   04

(for the given input step V is the last step).

 

Which of the following will be the last step for the given input ?

Input :- 03   31   43   22   11   09 

A) IV B) V
C) VI D) None of these
 
Answer & Explanation Answer: B) V

Explanation:

Clearly, in the given arrangement, the numbers have been arranged in descending order in a sequence, altering the position of only one number in each step

Input       : 03   31   43   22   11   09

Step I      : 43   03   31   22   11   09
Step II     : 43   31   03   22   11   09
Step III   : 43   31   22   03   11   09
Step IV   : 43   31   22   11   03   09
Step V    : 43   31   22   11   09   03

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17 6648
Q:

A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely ?

A) 4 hrs 15 min B) 3 hrs 24 min
C) 4 hrs 51 min D) 3 hrs 45 min
 
Answer & Explanation Answer: D) 3 hrs 45 min

Explanation:

Time taken by one tap to fill half of the tank = 3 hrs.

Part filled by the taps in 1 hour = 4 x 1/6 = 2/3

Remaining part = 1 - 1/2 = 1/2

2/3 : 1/2 :: 1 : p

p = 1/2 x 1 x 3/2 = 3/4 hrs. i.e., 45 min

So, total time taken = 3 hrs 45 min.

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Filed Under: Pipes and Cistern
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13 6639
Q:

In a public bathroom there are n taps 1,2,3...n. Tap1 and Tap2 take equal time to fill the tank while Tap3 takes half the time taken by Tap2 and Tap4 takes half the time taken by Tap3. Similarly each next number of tap takes half the time taken by previous number of Tap i.e, K-th Tap takes half the time taken by (K-1)th Tap. If the 10th tap takes 2 hours to fill the tank alone then what is the ratio of  efficiency of 8th tap and 12th tap, respectively?

A) 4:1 B) 5:3
C) 16:1 D) 1:16
 
Answer & Explanation Answer: D) 1:16

Explanation:

Time taken by 8th tap = 2 x 2 x 2= 8 hours

Time taken by 12th tap = 2x (1/2) x (1/2)  = 1/2 hour

Ratio of time taken by 8th tap and 12th tap = 8 : 1/2 =16:1

Therefore, Ratio of efficiencies of 8th tap and 12th tap =1:16

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Filed Under: Time and Work

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Q:

Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ?

A) 36 years B) 28 years
C) 32 years D) 40 years
 
Answer & Explanation Answer: C) 32 years

Explanation:

Let Shilpa's present age is p years

According to question,

p = 4(x+4) – 4(x–4)

p = 4x+16 – 4x+16

p = 32

Shilpa's present age = 32 years

Rajeev is four years older than Shilpa

=> Shilpa's present age = Rajeev's age 4 years before.

=> Rajeev's age 4 years before = 32 years.

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Filed Under: Problems on Ages
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14 6633
Q:

The arithmetic mean of the following numbers 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6 and 7, 7, 7, 7, 7, 7, 7 is   ?

A) 6 B) 9
C) 7 D) 5
 
Answer & Explanation Answer: D) 5

Explanation:

Arithmatic mean = sum/members 

=> (1x1 + 2x2 + 3x3 + 4x4 + 5x5 + 6x6 + 7x7) / (1 + 2 + 3 + 4 + 5 + 6 + 7)

=> 140/28 = 5

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Filed Under: Arithmetical Reasoning
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4 6633
Q:

Twelve percent of Kalyan's monthly salary is equal to the sixteen per cent of Nandu's monthly salary. Sarnesh's monthly salary is half that of Nandu's monthly salary. If sarnesh's annual salary is Rs. 1.08 lacs, What is Kalyan's monthly salary ?

A) 15,000 B) 36,000
C) 24,000 D) 12,500
 
Answer & Explanation Answer: C) 24,000

Explanation:

Let K = Kalyan's monthly salary
N = Nandu's monthly salary
S = Sarnesh's monthly salary.
Then from given data,
12% of K = 16% of N
S = N/2 => N = 2S
K = 16/12 x N = 16/12 x 2S
= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000

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Filed Under: Percentage
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4 6633
Q:

If Laxmi is taller than Ramya but shorter than Susmitha and Ramya is as tall as Hema but taller than Avanthi, then Hema is :

A) shorter than Ramya B) taller than Avanthi
C) taller than susmitha D) shorter than Laxmi
 
Answer & Explanation Answer: D) shorter than Laxmi

Explanation:

As given, we have:

Susmitha > Laxmi > Ramya; Ramya = Hema, Ramya > Avanthi

Thus the sequence of heights becomes:

Susmitha > Laxmi > Ramya = Hema > Avanthi

Clearly, Hema is shorter than Laxmi.

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Filed Under: Logical Sequence of Words
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