Aptitude and Reasoning Questions

No. of letters in the word = 6
No. of 'E' repeated = 2
Total No. of arrangement = 6!/2! = 360

Given total applicants = 135
Given graduates are G=60
Otherthan graduates=135-60 = 75
Given experienced candidates = 80
1) For maximum number of graduates have experience
    Total graduates to have experience = 60

2) For minimum number of graduates have experience
    Remaining after taking other than graduates in experience= 80-75 = 5

Look at the following table which shows the letters and their respective codes :

Letter     A     B     D     E     G     I     M     U     

Code       5     8     3     2     4     1     7     9

Therefore, the code for IMAGE is 17542

Interest received by L from K = 8% of half of Rs.40,000  

⇒8100×20000=1600  

Amount received by L per annum for being a working partner = 1200 x 12 = Rs.14,400

Let 'A' be the part of remaing profit that 'L' receives as his share.

 Total income of 'K' = only his share from the reamaing profit

                              = 'A', as both share equally.

Given income of L = Twice the income of K

--> (1600 + 14400 + A ) = 2A

--> A= Rs.16000

Thus total profit = 2A + Rs.14,400= 2(16000) + 14400 

                                                  = 32000 +14400 = Rs.46,400.

Screws weight = 90x100 = 9000gms
bolts weight = 100 x 150 = 15000gms
weight = screws + bolts => 24000 gms =>24 kg
Given entire box weight = 35.5kg
empty box = entire box weight - weight => 35.5kg - 24kg => 11.5kg
so the empty box is 11.5kg.

Let the ten's digit be x and unit's digit be y. Then, (10x + y) - (x + y) = 9 or x = 1.

From this data we cannot find  y, the unit's digit. So the data is inadequate..