Aptitude and Reasoning Questions

Q:

The average of 11 numbers is 10.9. If the average of the first six numbers is 10.5 and that of the last six numbers is 11.4, then the middle number is :

A) 10.5 B) 11.5
C) 12.5 D) 13.5
 
Answer & Explanation Answer: B) 11.5

Explanation:

Middle numbers  =  [(10.5 x 6 + 11.4 x 6) - 10.9 x 11] = (131.4 - 119-9) = 11.5.

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Filed Under: Average

103 60049
Q:

The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

A) 35 B) 36.5
C) 40 D) 42
 
Answer & Explanation Answer: B) 36.5

Explanation:

Correct Sum = (36 * 50 + 48 - 23) = 1825.

Correct mean = = 1825/50 = 36.5

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Filed Under: Average

183 60013
Q:

The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is 

A) 10 B) 46
C) 70 D) 90
 
Answer & Explanation Answer: A) 10

Explanation:

Let the numbers be x and (100-x).

 

Then,x100-x=5*495

 

 =>  x2-100x+2475=0

 

 =>  (x-55) (x-45) = 0

 

 =>  x = 55 or x = 45

 

  The numbers are 45 and 55

 

Required difference = (55-45) = 10

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Filed Under: HCF and LCM

151 59871
Q:

Q is the brother of R;

P is the sister of Q;

T is the brother of S;

S is the daughter of R.

Who are the cousins of Q ? 

A) R and P B) P and T
C) Q and T D) S and T
 
Answer & Explanation Answer: D) S and T

Explanation:

T is the brother of S, who is the daughter of R. So, T and S are the children of R. 

Now. Q is the brother of R. So, T and S are the cousins of Q. 

 

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Filed Under: Blood Relations

97 59821
Q:

Pointing out to a lady, a girl said, "She is the daughter-in-law of the grandmother of my father's only son." How is the lady related to the girl ?

A) Sister-in-law B) Mother
C) Aunt D) Can't be determined
 
Answer & Explanation Answer: D) Can't be determined

Explanation:

Girls's father's only son— Girl's brother. Daughter in law of girl’s grandmother can be their mother, or maternal uncle’s wife, i.e. aunt. So relation cannot be determined.

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Filed Under: Blood Relations

932 59623
Q:

A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used ?

A) 3 months B) 6 months
C) 10 months D) 12 months
 
Answer & Explanation Answer: C) 10 months

Explanation:

Let the total profit be Rs. z. Then,

B's share = Rs. 2z/3,  A's share = Rs. ( z - 2z/3 ) = Rs. z/3.

A : B = z/3 : 2z/3 = 1:2

Let the total capital be Rs, X and suppose B's money was used for x months. Then.

(1(x) / 4 * 15) / (3x) / 4 * y) = 1/2 <=> y = (15 * 2 / 3) = 10 .

 Thus, B's money was used for 10 months.

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Filed Under: Partnership

125 59516
Q:

If the diameter of a circle is 28 cm, then what will be its circumference (in cm)?

 

A) 88 B) 176
C) 35 D) 70
 
Answer & Explanation Answer: A) 88

Explanation:
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Filed Under: Area
Exam Prep: Bank Exams

0 59384
Q:

In the following question, select the odd letter/letters from the given alternatives.

 

A) GMS B) KQW
C) JPV D) NTY
 
Answer & Explanation Answer: D) NTY

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

3 59329