FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

Let O be the orthocentre of the triangle ABC. If ∠BOC = 150°, Then ∠BAC is

A) 30° B) 60°
C) 90° D) 120°
 
Answer & Explanation Answer: A) 30°

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0 1055
Q:

What is the angle between centripetal acceleration and tangential acceleration?

A) 90° B) 45°
C) 0° D) 180°
 
Answer & Explanation Answer: A) 90°

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0 1053
Q:

The area of a rhombus having one side 10 cm and one diagonal 12 cm is

A) 48 cm2 B) 96 cm2
C) 144 cm2 D) 192 cm2
 
Answer & Explanation Answer: B) 96 cm2

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0 1051
Q:

The perimeters of a square and an equilateral triangle are equal. If the diagonal of the square is 9 cm, what is the area of the equilateral triangle?

A) 18√3 sq cm B) 9√3 sq cm
C) 18√2 sq cm D) 9√2 sq cm
 
Answer & Explanation Answer: A) 18√3 sq cm

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0 1048
Q:

Find the maximum area of a rectangular field which is surrounded by a rope of 100 meters?

A) 500 sq.m B) 325 sq.m
C) 400 sq.m D) 100 sq.m
 
Answer & Explanation Answer: C) 400 sq.m

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2 1048
Q:

Find the area (in cm2) of a semi-circle of radius 28 cm.

A) 2464 B) 832
C) 1232 D) 1664
 
Answer & Explanation Answer: C) 1232

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1 1045
Q:

Find the greatest length which can be used to measure exactly three cloth pieces of lengths 1.26 m, 1.98 m and 1.62 m respectively.

A) 12 cm B) 14 cm
C) 16 cm D) 18 cm
 
Answer & Explanation Answer: D) 18 cm

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0 1039
Q:

The areas of two similar triangles ΔABC and ΔPQR are 36 sq cms and 9 sq cms respectively. If PQ = 4 cm then what is the length of AB (in cm)?

A) 16 B) 12
C) 8 D) 6
 
Answer & Explanation Answer: C) 8

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0 1037