FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

Find the radius of the circle if the area of its sector is 30.8 sq cm whose corresponding central angle is 72°?

A) 3.5 cm B) 7 cm
C) 14 cm D) 10.5 cm
 
Answer & Explanation Answer: B) 7 cm

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Q:

An angle is (2/3)rd of its supplementary angle. What is the measure of the angle?

A) 108° B) 72°
C) 54° D) 36°
 
Answer & Explanation Answer: B) 72°

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Q:

In an equilateral triangle of side 24 cms, a circle is inscribed touching its sides. The area of the remaining portion of the triangle is equal to

A) 36.6 sq. cm B) 54.2 sq. cm
C) 72.8 sq. cm D) 98.5 sq. cm
 
Answer & Explanation Answer: D) 98.5 sq. cm

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Q:

The area and the length of one of the diagonals of a rhombus is 84 cm² and 7 cm respectively. Find the length of its other diagonal (in cm).

A) 12 B) 24
C) 48 D) 36
 
Answer & Explanation Answer: B) 24

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Q:

In a triangle PQR, PX, QY and RZ be altitudes intersecting at O. If PO = 6 cm, PX = 8 cm and QO = 4 cm, then what is the value (in cm) of QY?

A) 6.3 B) 5.8
C) 6 D) 7
 
Answer & Explanation Answer: D) 7

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Q:

In the given figure, PQR is a triangle and quadrilateral ABCD is inscribed in it. QD = 2 cm, QC = 5 cm, CR = 3 cm, BR = 4 cm, PB = 6 cm, PA = 5 cm and AD = 3 cm. What is the area in sq.cm of the quadrilateral ABCD?

A) (23√21)/4 B) (15√21)/4
C) (17√21)/5 D) (23√21)/5
 
Answer & Explanation Answer: C) (17√21)/5

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Q:

In Δ ABC, the median AD is 8 cm and CB is 16 cm, measure of angle CAB is_____ .

A) 90° B) 30°
C) 60° D) 120°
 
Answer & Explanation Answer: A) 90°

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Q:

AB and AC are the two tangents to a circle whose radius is 6 cm. If ∠BAC = 60 deg, then what is the value (in cm) of (AB2 + AC2)?

A) 6√6 B) 4√6
C) 9√3 D) 8√3
 
Answer & Explanation Answer: A) 6√6

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