FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

If the area of a semi-circle is 1925 sq.cm, then find its radius (in cm).

 

A) 70 B) 31
C) 62 D) 35
 
Answer & Explanation Answer: D) 35

Explanation:
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Q:

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth.  The percentage of decrease in area is:

A) 18% B) 28%
C) 38% D) 48%
 
Answer & Explanation Answer: B) 28%

Explanation:

Let original length = x and original breadth = y.  

Decrease in area = xy - 80100x×90100y = (7/25)xy

 

Decrease % =    (7/25)xy * (1/xy) * 100 = 28%

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Q:

If the sum of the interior angles of a regular polygon is 720° then how many sides does it have?

 

A) 8 B) 9
C) 6 D) 10
 
Answer & Explanation Answer: C) 6

Explanation:
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Q:

 If the circumference of a circle is 88 cm, then what must be its area (in cm2)?

 

A) 1232   B) 616  
C) 704   D) 1408
 
Answer & Explanation Answer: B) 616  

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Q:

The area of an equilateral triangle is 49√3 cm2. Find its side (in cm).

 

A) 7 B) 14
C) 28 D) 42
 
Answer & Explanation Answer: B) 14

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Q:

The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?

A) 10cm B) 20cm
C) 30cm D) 40cm
 
Answer & Explanation Answer: B) 20cm

Explanation:

Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is 2x2

 

 

 

after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)=2x2+5x-25

since new area is 75 units greater than original area thus
2x2+75 = 2x+5x-25
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.

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29 18221
Q:

A typist uses a sheet measuring 20cm by 30cm lengthwise.If a margin of 2 cm is left on each side and a 3 cm margin on top and bottom, then percent of the page used for typing is

A) 64% B) 74%
C) 84% D) 94%
 
Answer & Explanation Answer: A) 64%

Explanation:

Area of the sheet = 20×30cm2  

Area used for typing = 20-4×30-6cm2   

required % =384600×100=64%

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Q:

One of the roots of the equation x2 - 6x + k = 0 is x = 2. The other root is

 

A) x = -1 B) x = 4
C) x = -4 D) x = 1
 
Answer & Explanation Answer: B) x = 4

Explanation:
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