Free Practice Questions for Competitive Exams, Interviews, Certifications

Q:

A person divided a sum of Rs. 17,200 into three parts and invested at 5%. 6% and 9% per annum simple interest. At the end of two years, he got the same interest on each part of money. What is the money invested at 9%?

A) Rs. 3,200	B) Rs. 4,000
C) Rs. 4,800	D) Rs. 5000

Answer & Explanation Answer: B) Rs. 4,000

Explanation:

Let sum invested @ 5% be P1, @ 6% be P2 then @ 9% =17200-(P1+P2)

So according to question

P1*5*2/100 = P2*6*2/100 or P1 = (6/5) P2

Also P2*6*2/100 = [17200-(P1+P2)]*9*2/100

Or 2 P2 = [17200–(11/5)P2] * 3

Or (2 + 33/5)P2 = 17200 * 3

P2 = 17200 * 3 * 5 / 43 = 6000

So P1 = 6/5 P2 = 7200

So Sum invested @ 9% = 17200–(6000+7200) = Rs 4000

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Filed Under: Simple Interest
Exam Prep: Bank Exams

1 2723

Q:

What is the least number of complete years in which a sum of money put out at 40% annual compound interest will be more than trebled?

A) 3	B) 4
C) 5	D) 6

Answer & Explanation Answer: B) 4

Explanation:

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Filed Under: Compound Interest
Exam Prep: Bank Exams

6 1667

Q:

A man who recently died left a sum of Rs. 3,90,000 to be divided among his wife, five sons and four daughters. He directed that each son should receive 3 times as much as each daughter receives and that each daughter receives and that each daughter should receive twice as much as their mother receives. What was the wife’s share?

A) Rs. 14,000	B) Rs. 12,000
C) Rs. 10,000	D) Rs. 9,000

Answer & Explanation Answer: C) Rs. 10,000

Explanation:

Let his wife get a share of Rs x

Each of the 4 daughters get = Rs 2x

Each of the 5 sons get = Rs 6x

So x + 4*2x + 5*6x = 390000

So 39x = 390000

X=10000 = wife’s share

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Filed Under: Partnership
Exam Prep: Bank Exams

5 2496

Q:

In an examination, 52% candidates failed in English and 42% failed in Mathematics. If 17% failed in both the subjects, then what percent passed in both the subjects?

A) 77	B) 58
C) 48	D) 23

Answer & Explanation Answer: D) 23

Explanation:

No of students failed in English only = 52 –17 = 35

No of students failed in maths only = 42 –17 = 25

Total no of failed students in either of the subjects = 35+17+25 = 77

No of passed student in both subjects = 100 –77 = 23

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams

0 1035

Q:

What is the value of $2 + \sqrt{2 + \sqrt{2 + \sqrt{2}}} . . . . . . .$

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: D) 4

Explanation:

Let 2+√2+√2..... = t
2+√t = t
t - 2 = √t
t = 4

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Filed Under: Simplification
Exam Prep: Bank Exams

0 1357

Q:

Tushar takes 6 hours to complete a piece of work, while Amar completes the same work in 10 hours. If both of them work together, then what is the time required to complete the work?

A) 3 hours	B) 3 hours 15 minutes
C) 3 hours 30 minutes	D) 3 hours 45 minutes

Answer & Explanation Answer: D) 3 hours 45 minutes

Explanation:

Let them take x hours working together

1/x = 1/10 + 1/6 = 8/30

X= 30/8 hours = 15/4 hours = 3 hours 45 minutes

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Filed Under: Time and Work
Exam Prep: Bank Exams

1 2862

Q:

Given that the polynomial $(x^{2} + ax + b)$ leaves that same remainder when by (x –1) or (x + 1) What are the values of a and b respectively?

A) 4 and 0	B) 0 and 3
C) 3 and 0	D) 0 and any interger

Answer & Explanation Answer: D) 0 and any interger

Explanation:

Since x^2+ ax + b when divided by x-1 or x+1 leaves the same remainder

So on putting x=1 and x=-1 we get the same value

1+a+b = 1-a+b

2a=0

a=0

here b can take any value as it will always get cancelled out

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Filed Under: Numbers
Exam Prep: Bank Exams

0 1053

Q:

If (4a +7b) (4c-7d) = (4a -7b) (4c +7d, then which one of the following is correct ?

A) a/b = c/d	B) a/d = c/b
C) a/b = d/c	D) none

Answer & Explanation Answer: A) a/b = c/d

Explanation:

(4a+7b)(4c-7d) = (4a-7b)(4c+7d)

(4a+7b)/(4a-7b) = (4c+7d)/(4c-7d)

Using componendo and dividendo

(4a+7b)+(4a-7b) / (4a+7b)-(4a-7b)

= (4c+7d)+(4c-7d) / (4c+7d)-(4c-7d)

Or 8a/14b = 8c/14d

Or a/b = c/d

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Filed Under: Simplification
Exam Prep: Bank Exams

3 3211

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