A cylindrical rod of iron, whose height is equal to its radius, is melted and cast into spherical balls whose radius is half the radius of the rod. Find the number of balls.
Volume of rod = πr2h = πr2×r = πr3
Volume of one spherical ball =r/2
Volume of the spherical ball = 43πr38
Number of balls=Volumeof rod/volumeof one ball
Find the surface area (in cm2) of a sphere of diameter 28 cm.
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