Q:
A alone can do a work in 20 days. B is 125% more efficient than A. A and B started working and worked for 4 days. If C alone completed the remaining job in 22 days. How many days C alone takes to complete the entire job?
Answer & Explanation
Answer: C) 40
Explanation: A alone can do = 20days
Efficiency ratio of A & B= 4 : 5
Time required will be in ratio = 5:4
B alone will do it in =16 days
LCM of (16,20)= 80 ,
Assume work size of 80 units
1 day work of A= 4 units 1 day work of B= 5 units
Work done by both in 4 days= 4*(5+4)= 36 units
Work left= 80-36= 44 units
Now C takes 22 days to complete= 44 units.
Time taken by C alone to complete the work= 40 days
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