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Technical Questions

Why Technical Knowledge?

In today's employment world, Information Technology plays major role. Technical knowledge along with Aptitude & Reasoning has become the doorway to software companies. When IT is extensively developing day to day, one should definitely acquire technical knowledge aiming to see career growth in software industry.


What in Technical Knowledge?

Programming Languages - to develop front end applications.

Database - to develop and maintain back end/ database applications.

Networking - understanding devices connected in network to communicate with each other as well as other networks.

Hardware - understanding processors, memory storage devices, Input & Output devices and more.

Operating System - to communicate between the software and Hardware in a computer.

Software Testing - the process of evaluating a system with the intend to satisfy specified requirements.


How to prepare for Technical Interviews?

One should be curious to knowledge updates; Software world is that place where you should keep updating with new market technology trends. Get some basic knowledge about all technical concepts as the logic remains same with any language and one can get the ease of working with any language in your company. Thoroughly get updates from your friends, IT magazines, Internet, News, etc. one can get knowledge from real time people through blogs.

Popular Latest Rated
Q:

Is Windows NT a full blown object oriented operating system? Give reasons.

Answer

No Windows NT is not so, because its not implemented in object oriented language and the data structures reside within one executive component and are not represented as objects and it does not support object oriented capabilities.

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Subject: Operating Systems

2 3218
Q:

What is object repository?

Answer

Object Repository means not a collection of objects


it's a common repository for all the people (testing, developers) for seeing all the data in single login.


for example QA wants to see 5 testers works then he goes  to each person login and see the data. It's very difficult job. for this we can use Object Repository.

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Subject: Hardware

0 3215
Q:

What are rings in Windows NT?

Answer

Windows NT uses protection mechanism called rings provides by the process to implement separation between the user mode and kernel mode.

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Subject: Operating Systems

0 3203
Q:

What is the use of MAU?

Answer

In token Ring , hub is called Multistation Access Unit(MAU).

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Subject: Networking
Job Role: Network Engineer

0 3198
Q:

Give two ways of converting a two input NAND gate to an inverter.

Answer

One way is shorting the two inputs of the NAND gate and passing the input.


truth table:


A B output


1 1 0


0 0 1


The second way is passing the input to only one input (say A) of the NAND gate. Since the other input  (say B is floating, it is always logic one.


Truth table:


A B output


1 1 0 


0 1 1

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Subject: Hardware

1 3194
Q:

 Which of the following improves a query's processing time?

A) Write complex queries. B) Combine a table with itself.
C) Query one query within another. D) Use compatible data types.
 
Answer & Explanation Answer: D) Use compatible data types.

Explanation:
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Filed Under: Database

0 3189
Q:

 Which of the following occurs when a transaction rereads data it has previously read and finds modification or deletions caused by a committed transaction?

A) Nonrepeatable read B) Phantom read
C) Dirty read D) Consistent read
 
Answer & Explanation Answer: A) Nonrepeatable read

Explanation:
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Filed Under: Database

0 3170
Q:

Point out the error, if any, in the following program.

#include "stdio.h"

main()

{

      unsigned char;

       FILE *fp;

       fp = fopen ("trail", "r");

       while (( ch = getc (fp)) ! = EOF)

               printf ("%c", ch);

       fclose (fp);

}  

Answer

EOF has been defined as #define EOF -1 n the file "stdio.h" and an unsigned char ranges from 0 to 255 hence when EOF is read from the file it cannot be accommodated in ch. Solution is to declare ch as an int.

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Subject: Programming

1 3168