Sawaal
  • Home/
  • Technical Questions

Technical Questions

Why Technical Knowledge?

In today's employment world, Information Technology plays major role. Technical knowledge along with Aptitude & Reasoning has become the doorway to software companies. When IT is extensively developing day to day, one should definitely acquire technical knowledge aiming to see career growth in software industry.


What in Technical Knowledge?

Programming Languages - to develop front end applications.

Database - to develop and maintain back end/ database applications.

Networking - understanding devices connected in network to communicate with each other as well as other networks.

Hardware - understanding processors, memory storage devices, Input & Output devices and more.

Operating System - to communicate between the software and Hardware in a computer.

Software Testing - the process of evaluating a system with the intend to satisfy specified requirements.


How to prepare for Technical Interviews?

One should be curious to knowledge updates; Software world is that place where you should keep updating with new market technology trends. Get some basic knowledge about all technical concepts as the logic remains same with any language and one can get the ease of working with any language in your company. Thoroughly get updates from your friends, IT magazines, Internet, News, etc. one can get knowledge from real time people through blogs.

Popular Latest Rated
Q:

public abstract interface Frobnicate { public void twiddle(String s); } 

Which is a correct class?

A) public abstract class Frob implements Frobnicate { public abstract void twiddle(String s) { } } B) public abstract class Frob implements Frobnicate { }
C) public class Frob extends Frobnicate { public void twiddle(Integer i) { } } D) public class Frob implements Frobnicate { public void twiddle(Integer i) { } }
 
Answer & Explanation Answer: B) public abstract class Frob implements Frobnicate { }

Explanation:

B is correct, an abstract class need not implement any or all of an interface’s methods

Report Error

View Answer Report Error Discuss

Filed Under: Programming

6 61094
Q:

How many times i value is checked in the below code?

       #include <stdio.h>
        int main()
        {
            int i = 0;
            do {
                i++;
                printf( "In while loopn" );
            } while (i < 3);
        }

A) 2 B) 3
C) 4 D) 1
 
Answer & Explanation Answer: B) 3

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Programming

8 47423
Q:

What will be output when you will execute following c code?

#include <stdio.h>
void main()

{
    int const SIZE = 5;
    int expr;
    double value[SIZE] = { 2.0, 4.0, 6.0, 8.0, 10.0 };
    expr=1|2|3|4;
    printf ( "%f", value[expr] );
}

A) 2.000000 B) 4.000000
C) 8.000000 D) Compilation error
 
Answer & Explanation Answer: D) Compilation error

Explanation:

Size of any array in c cannot be constantan variable.

Report Error

View Answer Report Error Discuss

Filed Under: Programming

7 47364
Q:

What will be output of following c code?

#include <stdio.h>
int main()

{
    int x=123;
    int i={
         printf("c" "++")
    };
    for(x=0;x<=i;x++){
         printf("%x ",x);
    }
    return 0;

}

Answer

Output: c++0 1 2 3

Explanation: First printf function will print: c++ and return 3 to variable i.For loop will execute three time and printf function will print 0, 1, 2 respectively.

Report Error

View answer Workspace Report Error Discuss

Subject: Programming

71 45622
Q:

main()

{

char *p; p = "Hello";

printf ("%cn", *&*p);

}

A) H B) Hello
C) Compilation error D) H E L L O
 
Answer & Explanation Answer: A) H

Explanation:

* is a dereference operator & is a reference operator. They can be applied any number of times provided it is meaningful. Here p points to the first character in the string "Hello". *p dereferences it and so its value is H. Again & references it to an address and * dereferences it to the value H

Report Error

View Answer Report Error Discuss

Filed Under: Programming
Job Role: Software Architect

26 45001
Q:

What is the cause of thrashing? How does the system detect thrashing? Once it detects thrashing, what can the system do to eliminate this problem?

Answer

Thrashing is caused by under allocation of the minimum number of pages required by a process, forcing it to continuously page fault. The system can detect thrashing by evaluating the level of CPU utilization as compared to the level of multiprogramming. It can be eliminated by reducing the level of multiprogramming.


 


What_is_the_cause_of_thrashing_How_does_the_system_detect_thrashing_Once_it_detects_thrashing,_what_can_the_system_do_to_eliminate_this_problem1557490890.jpg image

Report Error

View answer Workspace Report Error Discuss

Subject: Operating Systems

72 41205
Q:

main()

{

char s[ ] = "man";

int i;

for( i=0; s[ i ]; i++)

printf( "n%c%c%c%c", s[ i ], *(s+i), *(i+s), i[s] );

}

A) mmmm aaaa nnnn B) aaaa mmmm nnnn
C) nnnn aaaa mmmm D) None
 
Answer & Explanation Answer: A) mmmm aaaa nnnn

Explanation:

s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea.Generally array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of C it is same as s[i].

Report Error

View Answer Report Error Discuss

Filed Under: Programming

28 34219
Q:

Which of the following is not a database object in MS Access?

A) Reports B) Relationships
C) Tables D) Queries
 
Answer & Explanation Answer: B) Relationships

Explanation:

Queries, reports and tables are all related to database and relationships are not the database object and it is related to functions in mathyematics.

 Which_of_the_following_is_not_a_database_object_in_MS_Access1558073404.png image

Report Error

View Answer Report Error Discuss

Filed Under: Database
Exam Prep: Bank Exams
Job Role: Project Manager , IT Trainer , Database Administration , Bank Clerk , Analyst

16 28430