If 3a=4b=6c and a+b+c=2729, then a2+b2+c2 =?
4b=6c⇒b=32c and 3a=4b⇒a=43b=43(32c)=2c
a+b+c=2729 ⇒2c+32c+c=2729 ⇒c=629
∴a2+b2+c2=(a+b+b)2-2(ab+bc+ca)
=(2729)2-22c×32c+32c×c+c×2c
=729×29-2×132 c2
= 87
Find the square root of 1471369.
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