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Q:

Use continuity to evaluate the limit.

limx→128+x8+x

 

A) 1 B) 2
C) 4 D) 0

Answer:   A) 1



Explanation:

Since, we have that,

The numerator and denominator is (8+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to .

Thus, the limit exists and is given by,

limx→128+x8+x = 8+128+12= 1.

 

 

 

Subject: Simplification
Exam Prep: Bank Exams , CAT
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