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Q:
A) 55 | B) 56 |
C) 60 | D) 64 |
Answer: B) 56
Explanation:
Explanation:
In the below equation,
x2–15x + r = 0
sum of roots = p + q = -(-15)/1 = 15 (sum of roots for equation ax2+ bx + c is -b/a)
product of roots = pq = r/1 = r (product of roots for equation ax2+ bx + c is c/a)
given p –q = 1
also we know that p+q = 15
subtracting the squares of both
(p+q)2 + (p-q)2 = 15^2–1
p2 + q2 + 2pq –p2 –q2 +2pq = 225 -1
4pq = 224
4r = 224
r = 56