Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to ___ ?
xz = y2 10(0.48z) = 10(2 x 0.70) = 101.40
0.48z = 1.40
z = 140/18 = 35/12 = 2.9 (approx.)
1.123 + 11.23 + 112.3 = ?
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