Sawaal
1
Q:

3x2-14x+16=05y2-16y+12=0

A) x > y B) x < y
C) x=y or relation cannot be established between x and y D) x ≥ y

Answer:   C) x=y or relation cannot be established between x and y



Explanation:

3x2 – 14x + 16=0

3x2 –6x – 8x + 16=0

3x (x-2) – 8 (x-2)

(3x-8) (x-2)=0

x=8/3 or 2

5y2 – 16y + 12=0

5y2 – 10y – 6y + 12=0

5y (y-2) – 6 (y-2)=0

(5y-6) (y-2)=0

y=6/5 or 2

Can't be determined.

Subject: Simplification
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