Q:
Each question contains Quantity I and Quantity II. Read the contents carefully and answer your questions accordingly.
Quantity I: there are three numbers in the ratio 5:6:10. The sum of the largest and the smallest numbers is 126 more than the other number. Find the largest number?
Quantity II: 12% of first number is equal to 25 % second number. The difference of these two numbers is 78. Then find the largest number?
Answer & Explanation
Answer: C) Quantity I < Quantity II
Explanation: Quantity I= Let the three numbers will be 5x, 6x and 10x respectively
ATQ
10x+5x−6x=126
9x=126 X=14
So largest number =10x=10×14=140
Quantity II=let x and y are two numbers
ATQ
12% of x=25%of y And their difference is 78
So first no.=150 2nd no.=72
Hence Quantity I < Quantity II
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