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Q:

If (3/2)X = (5/7)Y = (6/5)Z, then what is X : Y : Z?

 

A) 105 : 50 : 84 B) 24 : 25 : 32
C) 15 : 21 : 25 D) 20 : 42 : 25

Answer:   D) 20 : 42 : 25



Explanation:
Subject: Ratios and Proportions
Exam Prep: Bank Exams
Q:

The incomes of two persons A and B are in the ratio 3 : 4. If each saves Rs.100 per month, the ratio of their expenditures is Rs. 1 : 2. Find their incomes.

A) Rs. 100 and Rs.150 B) Rs. 150 and Rs.200
C) Rs.200 and Rs.250 D) Rs.250 and Rs.300
 
Answer & Explanation Answer: B) Rs. 150 and Rs.200

Explanation:

Let the incomes of A and B be 3P and 4P.

If each saves Rs. 100 per month, then their expenditures = Income - savings = (3P - 100) and (4P - 100).

 

The ratio of their expenditures is given as 1 : 2.

Therefor, (3P - 100) : (4P - 100) = 1 : 2

Solving, We get P = 50. Substitute this value of P in 3P and 4P.

Thus, their incomes are : Rs.150 and Rs.200

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43 19388
Q:

Divide Rs.6500 among A,B and C so that after spending 90% , 75% and 60% of their respective saving were in the ratio of 3: 5: 6

Answer

A's spending 90%              \inline \therefore   saving = 10%


B's spending 75%              \therefore   saving = 25%


C's spending 60%              \inline \therefore   saving = 40%


Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.


\inline \therefore 10% of A's saving = Rs.3


100% of A's saving = \inline \frac{3}{10}\times 100 = Rs. 30


25% of B's saving = Rs. 5


100% of B's saving = \inline \frac{5}{25}\times 100 = Rs. 20


40% of C's saving = Rs.6


100% of C's saving = \inline \frac{6}{40}\times 100 = Rs. 15


Divide Rs. 6500 in the ratio of 30 : 20 : 15 as


A's Share  =  \inline \frac{30}{65}\times 6500 = Rs. 3000


B's Share   = \inline \frac{20}{65}\times 6500 = Rs. 2000


C's Share  = \inline \frac{15}{65}\times 6500 = Rs. 1500

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Subject: Ratios and Proportions
Job Role: Bank PO

66 9126
Q:

What is the third proportional to 16 and 36 ?

Answer

Let  \inline 6:8::15:x


\inline 16x=36\times 36


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73 14098
Q:

There are two containers, the first one contains 1 litre pure water and the second one contains 1 litre pure milk.Now 5 cups of water from the first container is taken out  is mixed well in the second container. Then, 5 cups of this mixture is taken out and is mixed in the first container. Let A denote the proportion of milk in the first container and B denote the proportion of water in the second container then:

A) A B) A=B
C) A>B D) can't be determined
 
Answer & Explanation Answer: B) A=B

Explanation:

Here the ratio of mixtures( i.e milk , water) doesnot matter. But the important point is that whether the total amount ( either pure or mixture ) being transferred is equal or not.Since the total amount ( i.e 5 cups) being transferred from each one to another , hence A =B.

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18 12849
Q:

Alloy A contains 40% gold and 60% silver. Alloy B contains 35% gold and 40% silver and 25% copper. Alloys A and B  are mixed in the ratio of 1:4 .What is the ratio of gold and silver in the newly formed alloy is?

A) 20% and 30% B) 36% and 44%
C) 25% and 35% D) 49% and 36%
 
Answer & Explanation Answer: B) 36% and 44%

Explanation:

Assume the weight of alloy a is 100 kg 

Therefore, The weight of alloy B is 400kg

 

             Gold          silver         copper

 

    A       40kg          60kg          0kg

 

    B      140kg         160kg        100kg

 

  total    180kg          220kg        100kg

 

Therefore, Ratio of gold and silver in new alloy = 180500:200500= 36% :44%

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100 28387
Q:

The number of oranges in three baskets are in the ratio of 3 : 4 : 5. In which ratio the no. of oranges in first two baskets must be increased so that the new ratio   becomes 5 : 4 : 3?

A) 1:3 B) 2:1
C) 3:4 D) 2:3
 
Answer & Explanation Answer: B) 2:1

Explanation:

Let,   B1 : B2 : B3 = 3x : 4x : 5x 

 

again  B1 : B2 : B3 = 5y : 4y : 3y

 

Since there is increase in no.of oranges in first two baskets only, it means the no. of oranges remains constant in the third basket

 

Therefore,   5x = 3y

 

Hence    3x : 4x : 5x   =>   9y5:12y5:15y5 = 9y:12y:15y

 

and       5y : 4y : 3y   =>   25x : 20x : 15x

 

Therfore, increment in first basket = 16

 

Increment in second basket = 8

 

Thus, required ratio = 16/8 = 2:1

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88 22106
Q:

In a zoo, there are rabbits and pigeons. If heads are counted, there are 340 heads and if legs are counted there are 1060 legs.How many pigeons are there?

A) 120 B) 150
C) 170 D) 180
 
Answer & Explanation Answer: B) 150

Explanation:

Suppose there are all the pigeons then total no of heads are 340 and total no of legs are 680. 

 

Now, since 380 (1060-680) legs are extra, it means there will be 190 (380/2) rabbits.As we know a rabbit has two extra legs than that of a pigeon.

 

Therefore,  number of rabbits =190

 

and number of pigeons = 340- 190 = 150

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165 41520
Q:

In Maa Yatri Temple every devotee offers fruits to the orphans. Thus every orphan receives bananas, oranges and grapes in the ratio of 3:2:7 in terms of dozens. But the weight of a grape is 24 gm and  weight of a banana and an orange are in the ratio of 4:5, while the weight of an orangeis 150gm. Find the ratio of all the three fruits in terms of weight, that an orphan gets

A) 90:75:42 B) 180:150:82
C) 75:42:90 D) None of these
 
Answer & Explanation Answer: D) None of these

Explanation:

Ratio of fruits (by dozen) = 3:2:7

Ratio of fruits (by weight) =  120 :150: 24

Therefore, Ratio of fruits (combined) by weight = 3 x 120 : 2 x 150 : 7 x 24 = 30 : 25 : 14 

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16 15231