0
Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only

Answer:   D) Either II or III only



Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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A circle and a square have same area. The ratio of the side of the square to the radius of the circle will be:

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The profit (in Rs.) after selling an article for Rs.524 is the same as the loss (in Rs.) after selling it for Rs.452. The cost price of the article is:

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C) Rs.488 D) Rs.500
 
Answer & Explanation Answer: C) Rs.488

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Ravi has a roadmap with a scale of 1.5 cm for 18 km. He drives on that road for 72 km. What would be his distance covered in that map.

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A watch is listed for Rs.230 and is sold at a discount of 12%, then the sale price of the watch is

A) Rs.27.6 B) Rs.276
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The diagonal of a cube is 192  cm. Its volume in cm3 will be 

A) 216 B) 432
C) 512 D) 624
 
Answer & Explanation Answer: C) 512

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A and B together can do a piece of work in 12 days while A alone can do the same work in 30 days. B alone can do it in

A) 18 days B) 20 days
C) 15 days D) 22 days
 
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Find equation of the perpendicular bisector of segment joining the points (2,-5) and (0,7)?

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