0
Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only

Answer:   D) Either II or III only



Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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The percentage change of a number when it is first decreased by 10% and then increased by 10% is

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A) 100489 B) 100000
C) 100256 D) 100225
 
Answer & Explanation Answer: A) 100489

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Two circles of radii 17 cm and 8 cm are concentric. The length of a chord of greater circle which touches the smaller circle is

A) 15 cm B) 16 cm
C) 30 cm D) 34 cm
 
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If a+b-62+a2b2+1+2b=2ab+2a, then the value of a is 

A) 7 B) 6
C) 3.5 D) 2.5
 
Answer & Explanation Answer: C) 3.5

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Q:

The simplification value of 735+2-552+7+227+5 is

A) 0 B) 1
C) 5 D) 6
 
Answer & Explanation Answer: A) 0

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Q:

In a class, average height of all students is 'a' cms. Among them, average height of 10 students is 'b' cms and the average height of the remaining students is 'c' cms. Find the number of students in the class. (Here a>c and b>c )

A) (a(b-c))/(a-c) B) ((b-c)/(a-c))
C) ((b-c)/10(a-c)) D) (10(b-c))/(a_c))
 
Answer & Explanation Answer: D) (10(b-c))/(a_c))

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