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                              Q:
                           
                           
                                                      | A) 11/20 | B) 43/120 | 
| C) 77/120 | D) 9/20 | 
                              Answer:   C) 77/120
                              
                                                            
                              
Explanation:
                               
                           
                           Explanation:
At least one black can be chosen in two ways from each box:
Now, probability of choosing at least one black ball from first box 
= 1/2 × [ (2C1× 2C1)/4C2 + 2C2/ 4C2 ]= 5/12
Probability of choosing at least one black ball from 2nd box
= 1/2 × [(4C1×12C1)/16C2 + 4C2/ 16C2] = 9/40
Final probability
= 5/12 + 9/40 = (50 + 27)/120 = 77/120
 
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