0
Q:

What is the compound interest earned at the end of 3 years?

I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.

II.The rate of interest is 10 p.c.p.a.

III.Compound interest for 3 years is more than the simple interest for that period by Rs.465.

A) I and II only B) II and III only
C) I and III only D) Either II or III only

Answer:   D) Either II or III only



Explanation:

 

 

 

 

 

 

I. gives, S.I for 3 years = Rs. 4500.

 

 

 

II. gives, Rate = 10% p.a.

 

 

 

III. gives, (C.I.) - (S.I.) = Rs. 465.

 

 

 

Clearly, using I and III we get C.I. = Rs. (465 + 4500).

 

 

 

Thus, II is redundant.

 

 

 

Also, from I and II, we get sum =

 

 

 

100 x 4500

 

 

 

= 15000.

 

 

 

10 x 3

 

 

 

Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.

 

 

 

Thus, III is redundant.

 

 

 

Either II or III is redundant.

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In a triangle ABC, AB = 8 cm, AC = 10 cm and ∠B = 90°, then the area of ΔABC is

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C) 25 sq.cm D) 24 sq.cm
 
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The perimeter of two similar triangles ABC and PQR are 36 cms and 24 cms respectively. If PQ = 10 cm then the length of AB is

A) 18 cm B) 12 cm
C) 15 cm D) 330 cm
 
Answer & Explanation Answer: C) 15 cm

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If 2+x+2-x2+x-2-x=2, then the value of X is

A) 4⁄5 B) 3⁄5
C) 8/5 D) 1/5
 
Answer & Explanation Answer: C) 8/5

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If (a+1a)2=3, then the value of a6-1a6 will be

A) 1 B) 3
C) 0 D) 2
 
Answer & Explanation Answer: C) 0

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The average of 12 numbers is 9. If each number is multiplied by 2 and added to 3, the average of the new set of numbers is

A) 9 B) 18
C) 21 D) 27
 
Answer & Explanation Answer: C) 21

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Q:

(251+252+253+254+255) is divided by

A) 23 B) 58
C) 124 D) 127
 
Answer & Explanation Answer: C) 124

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Q:

If tan 450=cot, then the value of , in radians is 

A) π B) π9
C) π2 D) π12
 
Answer & Explanation Answer: B) π9

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