Number Puzzles Questions

Here the puzzle follows the logic that

Right side number = sum of the number on the left side and the previous number on the left side

=> 6 = 4+2

=> 10 = 6+4

=> ? = 16+10 = 26.

Here the given Number Puzzle follows a pattern that, Sum of the numbers on the corners on the two squares is same and is equal to 54.

i.e,

13 + 15 + 14 + 12 = 54 

and

8 + 22 + 9 + 15 = 54

Given 

1 = 1 => 1 x 11 = 11

2 = 22 => 2 x 11 = 22

3 = 33 => 3 x 11 = 33

...

...

Similarly,

11 => 11 x 11 = 121.

Logic is

1st fig : 9x2 + 5 = 23

2nd fig : 6x3 + 4 = 22

3rd fig : Nx4 + 5 = 9 => N = 1.

In each triangle, multiply the lower two numbers together and add the upper number to give the value at the centre.

1 + 1 = 121 = 1x1 1+1 1x1

1 + 2 = 134 = 1x1 1+2 2x2

2 + 2 = 444 = 2x2 2+2 2x2

3 + 2 = 954 = 3x3 3+2 2x2

3 + 3 = ?   

Similarly, 3x3 3+3 3x3 = 969

In each circle,lower number equals the product of the top two numbers, subtracting 3 for the left hand circle, 4 for the middle, and 5 for the right hand circle.

Sum of numbers in all individual boxes must be equal.

Here sum must be equal to 30.

=> x + 14 + 9 + 2 = 30 => x = 5.