What will be output when you will execute following c code?

#include <stdio.h>
void main()

{
     switch(2)

      {
            case 1L:printf("No");
            case 2L:printf("%s","I");
              goto Love;
            case 3L:printf("Please");
            case 4L:Love:printf("Hi");
     }
}

int a = 1, b , dummy;

a > 10 ? b = 20 : dummy =1;

Note that the following would not have worked:

a > 10 ? b = 20 : ;;

Constant expression required in the second case, we cannot use j.

The condition in the while loop is a must.

Here we are initalising the function pointer p to the address of the function fun(). But during this initialisation the function has not been defined. Hence an error.

To eliminate this error add the prototype of the fun() before declaration of p, as shown below:

extern int fun();    or simply  int fun();

Error occurs because we have mixed the ANSI prototype with K & R style of function definition.

When we use ANSI prototype for a function and pass a float to the function it is promoted to a double. When the function accepts this double into a float a type mismatch occurs hence the error.

The remedy for this error could be to define the function as :

int fun (float aa)

{

  ....

}

There is no difference except for the fact that the first one gives a hint that the function fun() is probably in another source file.

extern int i is a declaration and not a definition, hence Error occured.

#include<stdio.h>
int main(){
  FILE *p,*q;
  char file1[20],file2[20];
  char ch;
  printf("\nEnter the source file name to be copied:");
  gets(file1);
  p=fopen(file1,"r");
  if(p==NULL){
      printf("cannot open %s",file1);
      exit(0);
  }
  printf("\nEnter the destination file name:");
  gets(file2);
  q=fopen(file2,"w");
  if(q==NULL){
      printf("cannot open %s",file2);
      exit(0);
  }
  while((ch=getc(p))!=EOF)
      putc(ch,q);
  printf("\nCOMPLETED");
  fclose(p);
  fclose(q);
 return 0;
}