Sawaal
28
Q:

main()

{

char s[ ] = "man";

int i;

for( i=0; s[ i ]; i++)

printf( "n%c%c%c%c", s[ i ], *(s+i), *(i+s), i[s] );

}

A) mmmm aaaa nnnn B) aaaa mmmm nnnn
C) nnnn aaaa mmmm D) None

Answer:   A) mmmm aaaa nnnn



Explanation:

s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea.Generally array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of C it is same as s[i].

Subject: Programming
Related Questions
Q:

What would be the output of the following program?

main()

{

    printf (" %d%d%d ", sizeof (3.14f), sizeof (3.14), sizeof (3. 141);

}

Answer

4  8  10

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Subject: Programming

0 1870
Q:

Which error are you likely to get when you run the following program?

main()

{

  struct emp

  {

      char name[20];

      float sal;

  };

  struct emp e[10];

  int i;

  for ( i = 0 ; i <= 9; i++)

        scanf ( "%s %f" , e[i].name, &e[i].sal );

}

Answer

Floating point formats not linked

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Subject: Programming

0 1853
Q:

We want to round off x, a Float to an Int value. The correct way to do so would be

A) Y = ( int ) ( x + 0.5 ) ; B) Y = int ( x + 0.5) ;
C) Y = ( int ) x + 0.5; D) Y = ( int ) ( ( int ) x + 0.5 )
 
Answer & Explanation Answer: A) Y = ( int ) ( x + 0.5 ) ;

Explanation:

Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.

 

y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)

 

Example:

 

#include

 

int main ()

 

{

 

  float x = 2.6;

 

  int y = (int)(x + 0.5);

 

  printf ("Result = %d\n", y );

 

  return 0;

 

}

 

Result : 3

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Filed Under: Programming

2 5439
Q:

What would be the output of the following program?

main()

{

    int i = -3, j =2, k =0, m ;

    m = ++j && ++i || ++k ;

    Printf ( "\n%d%d%d%d", i , j , k , m );

}

Answer

-2  3  0  1

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Subject: Programming

1 1859
Q:

In the following code in which order the functions would be called?

a = ( f1 ( 23,14 ) * f2 ( 12/4) ) + f3() ;

Answer

The order may vary from compiler to compiler.


Here the multiplication will happen before the addition , but in which order the functions would be called is undefined. In an arithmetic expression the parentheses tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parentheses first.

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Subject: Programming

0 1880
Q:

Can you suggest any other way of writing the following expression such that 30 is used only once?

a <= 20 ? b = 30 : c = 30 ;

Answer

*( ( a <= 20 ) ? &b : &c ) = 30;

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Subject: Programming

1 2057
Q:

What would be the output of the following program?

main()

{

  int i=2 ;

  printf ("\n%d%d", ++i, ++i );

}

Answer

Output may vary from compiler to compiler.


The order of evaluation of the arguments to a function call is unspecified.

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Subject: Programming

0 1769
Q:

What would be the output of the following program?

main()

{

    static int a[20];

    int i = 0;

    a[i] = i++;

    printf ("\n%d%d%d", a[0],  a[1], i);

}

Answer

0  0  1


That's what some of the compilers would give. But some other compiler may give a different answer. The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined.

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Subject: Programming

0 1966