Sawaal
28
Q:

main()

{

char s[ ] = "man";

int i;

for( i=0; s[ i ]; i++)

printf( "n%c%c%c%c", s[ i ], *(s+i), *(i+s), i[s] );

}

A) mmmm aaaa nnnn B) aaaa mmmm nnnn
C) nnnn aaaa mmmm D) None

Answer:   A) mmmm aaaa nnnn



Explanation:

s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea.Generally array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of C it is same as s[i].

Subject: Programming
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main()

{

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}

Answer

main()


{


   char *str[] = { "Frogs", "Do", "Not", "Die." , "They", "Croak!" };


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What would be the output of the following program, if the array beigns at address 65486?

main()

{

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0 1900
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What would be the output of the following program?

main()

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    char *b = "Visual C++";

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1 1868
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How would you obtain segment and offset addresses from a far address of a memory location?

Answer

#include "dos.h"


main()


{


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0 2155
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How would you eliminate the warning generated on complaining the following program?

main()

{

  char far *scr;

  scr = 0xB8000000;

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Answer

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0 1725
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Would the following program compile?

main()

{

    int a = 10, *j;

    void *k;

    J = k = &a;

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0 2417
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What would be the output of the following program assuming that the array beigns at location 1002?

main()

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}

Answer

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Subject: Programming

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