13
Q:

#define clrscr() 100

main()

{

clrscr();

printf( "%dn", clrscr() );

}

A) 100 B) 0
C) Compilation error D) Exception occurs

Answer:   A) 100



Explanation:

Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :

main ()

{

100;

printf("%d\n",100);

}

Note: 100; is an executable statement but with no action. So it doesn't give any problem.

Subject: Programming
Q:

Write a c program to find out sum of diagonal element of a matrix.

Answer

#include<stdio.h>

int main(){

  int a[10][10],i,j,sum=0,m,n;

  printf("\nEnter the row and column of matrix: ");
  scanf("%d %d",&m,&n);

  printf("\nEnter the elements of matrix: ");
  for(i=0;i<m;i++)
      for(j=0;j<n;j++)
           scanf("%d",&a[i][j]);
  printf("\nThe matrix is\n");

  for(i=0;i<m;i++){
      printf("\n");
      for(j=0;j<m;j++){
      printf("%d\t",a[i][j]);
      }
 }
 for(i=0;i<m;i++){
     for(j=0;j<n;j++){
          if(i==j)
              sum=sum+a[i][j];
     }
 }
 printf("\n\nSum of the diagonal elements of a matrix is: %d",sum);

 return 0;
}

Sample output:

Enter the row and column of matrix: 3 3
Enter the elements of matrix:
2
3
5
6
7
9
2
6
7
The matrix is
2       3       5
6       7       9
2       6       7
Sum of the diagonal elements of a matrix is: 16

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Subject: Programming

1 3781
Q:

Write a program for matrix multiplication in c

Answer

#include <stdio.h>


int main() {


  int a[5][5], b[5][5], c[5][5], i, j, k, sum = 0, m, n, o, p;


  printf( "\nEnter the row and column of first matrix" );


  scanf( "%d %d", &m, &n );


  printf( "\nEnter the row and column of second matrix" );


  scanf( "%d %d", &o, &p );


  if(n!=o) {


      printf( "Matrix mutiplication is not possible" );


      printf( "\nColumn of first matrix must be same as row of second matrix" );


  }


  else {


      printf( "\nEnter the First matrix" );


      for( i=0; i<m; i++ )


      for( j=0; j<n; j++ )


           scanf( "%d", &a[i][j] );


      printf( "\nEnter the Second matrix" );


      for( i=0; i<o; i++ )


      for( j=0; j<p; j++ )


           scanf( "%d", &b[i][j] );


      printf( "\nThe First matrix is\n" );


      for( i=0; i<m; i++ ) {


      printf("\n");


      for( j=0; j<n; j++ ) {


           printf( "%d\t", a[i][j] );


      }


      }


      printf( "\nThe Second matrix is\n" );


      for( i=0; i<o; i++ ) {


      printf("\n");


      for( j=0; j<p; j++ ) {


           printf( "%d\t", b[i][j] );


      }       


      }


      for( i=0; i<m; i++ )


      for( j=0; j<p;j++ )


           c[i][j] = 0;


      for( i=0; i<m; i++ ) { //row of first matrix


      for( j=0; j<p; j++ )  {  //column of second matrix


           sum = 0;


           for( k=0; k<n; k++ )


               sum = sum + a[i][k]*b[k][j];


           c[i][j] = sum;


      }


      }


  }


  printf( "\nThe multiplication of two matrix is\n" );


  for( i=0; i<m; i++ ) {


      printf("\n");


      for( j=0; j<p; j++ ) {


           printf( "%d\t", c[i][j] );


      }


  }


  return 0;


}

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Subject: Programming

0 2046
Q:

Write a c program for binary search.

Answer

#include<stdio.h>
int main(){

    int a[10],i,n,m,c=0,l,u,mid;

    printf("Enter the size of an array: ");
    scanf("%d",&n);

    printf("Enter the elements in ascending order: ");
    for(i=0;i<n;i++){
         scanf("%d",&a[i]);
    }

    printf("Enter the number to be search: ");
    scanf("%d",&m);

    l=0,u=n-1;
    while(l<=u){
         mid=(l+u)/2;
         if(m==a[mid]){
             c=1;
             break;
         }
         else if(m<a[mid]){
             u=mid-1;
         }
         else
             l=mid+1;
    }
    if(c==0)
         printf("The number is not found.");
    else
         printf("The number is found.");

    return 0;
}

Sample output:
Enter the size of an array: 5
Enter the elements in ascending order: 4 7 8 11 21
Enter the number to be search: 11
The number is found.

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Subject: Programming

0 2397
Q:

Write a c program for linear search.

Answer

#include<stdio.h>
int main(){

    int a[10],i,n,m,c=0;

    printf("Enter the size of an array: ");
    scanf("%d",&n);

    printf("Enter the elements of the array: ");
    for(i=0;i<=n-1;i++){
         scanf("%d",&a[i]);
    }

    printf("Enter the number to be search: ");
    scanf("%d",&m);
    for(i=0;i<=n-1;i++){
         if(a[i]==m){
             c=1;
             break;
         }
    }
    if(c==0)
         printf("The number is not in the list");
    else
         printf("The number is found");

    return 0;
}

Sample output:
Enter the size of an array: 5
Enter the elements of the array: 4 6 8 0 3
Enter the number to be search: 0
The number is found

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Subject: Programming

2 6830
Q:

Write a c program for merge sort.

Answer

#include
#define MAX 50

void mergeSort(int arr[],int low,int mid,int high);
void partition(int arr[],int low,int high);

int main(){
  
    int merge[MAX],i,n;

    printf("Enter the total number of elements: ");
    scanf("%d",&n);

    printf("Enter the elements which to be sort: ");
    for(i=0;i<n;i++){
         scanf("%d",&merge[i]);
    }

    partition(merge,0,n-1);

    printf("After merge sorting elements are: ");
    for(i=0;i<n;i++){
         printf("%d ",merge[i]);
    }

   return 0;
}

void partition(int arr[],int low,int high){

    int mid;

    if(low<high){
         mid=(low+high)/2;
         partition(arr,low,mid);
         partition(arr,mid+1,high);
         mergeSort(arr,low,mid,high);
    }
}

void mergeSort(int arr[],int low,int mid,int high){

    int i,m,k,l,temp[MAX];

    l=low;
    i=low;
    m=mid+1;

    while((l<=mid)&&(m<=high)){

         if(arr[l]<=arr[m]){
             temp[i]=arr[l];
             l++;
         }
         else{
             temp[i]=arr[m];
             m++;
         }
         i++;
    }

    if(l>mid){
         for(k=m;k<=high;k++){
             temp[i]=arr[k];
             i++;
         }
    }
    else{
         for(k=l;k<=mid;k++){
             temp[i]=arr[k];
             i++;
         }
    }
  
    for(k=low;k<=high;k++){
         arr[k]=temp[k];
    }
}


Sample output:

Enter the total number of elements: 5
Enter the elements which to be sort: 2 5 0 9 1
After merge sorting elements are: 0 1 2 5 9

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Subject: Programming

0 2078
Q:

Write a c program for insertion sort.

Answer

#include<stdio.h>
int main(){

  int i,j,s,temp,a[20];

  printf("Enter total elements: ");
  scanf("%d",&s);

  printf("Enter %d elements: ",s);
  for(i=0;i<s;i++)
      scanf("%d",&a[i]);

  for(i=1;i<s;i++){
      temp=a[i];
      j=i-1;
      while((temp<a[j])&&(j>=0)){
      a[j+1]=a[j];
          j=j-1;
      }
      a[j+1]=temp;
  }

  printf("After sorting: ");
  for(i=0;i<s;i++)
      printf(" %d",a[i]);

  return 0;
}

Output:
Enter total elements: 5
Enter 5 elements: 3 7 9 0 2
After sorting:  0 2 3 7 9

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Subject: Programming

0 2615
Q:

Write a c program for quick sort.

Answer

#include<stdio.h>

void quicksort(int [10],int,int);

int main(){
  int x[20],size,i;

  printf("Enter size of the array: ");
  scanf("%d",&size);

  printf("Enter %d elements: ",size);
  for(i=0;i<size;i++)
    scanf("%d",&x[i]);

  quicksort(x,0,size-1);

  printf("Sorted elements: ");
  for(i=0;i<size;i++)
    printf(" %d",x[i]);

  return 0;
}

void quicksort(int x[10],int first,int last){
    int pivot,j,temp,i;

     if(first<last){
         pivot=first;
         i=first;
         j=last;

         while(i<j){
             while(x[i]<=x[pivot]&&i<last)
                 i++;
             while(x[j]>x[pivot])
                 j--;
             if(i<j){
                 temp=x[i];
                  x[i]=x[j];
                  x[j]=temp;
             }
         }

         temp=x[pivot];
         x[pivot]=x[j];
         x[j]=temp;
         quicksort(x,first,j-1);
         quicksort(x,j+1,last);

    }
}

Output:
Enter size of the array: 5
Enter 5 elements: 3 8 0 1 2
Sorted elements: 0 1 2 3 8

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Subject: Programming

0 2492
Q:

Write a c program for selection sort.

Answer

include<stdio.h>
int main(){

  int s,i,j,temp,a[20];

  printf("Enter total elements: ");
  scanf("%d",&s);

  printf("Enter %d elements: ",s);
  for(i=0;i<s;i++)
      scanf("%d",&a[i]);

  for(i=0;i<s;i++){
      for(j=i+1;j<s;j++){
           if(a[i]>a[j]){
               temp=a[i];
              a[i]=a[j];
              a[j]=temp;
           }
      }
  }

  printf("After sorting is: ");
  for(i=0;i<s;i++)
      printf(" %d",a[i]);

  return 0;
}

Output:
Enter total elements: 5
Enter 5 elements: 4 5 0 21 7
The array after sorting is:  0 4 5 7 21

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Subject: Programming

0 2147