2
Q:
A) 1 km | B) 600 m |
C) 4.8 km | D) 1.2 km |
Answer:
Explanation:
Explanation:
Let length of platform be ‘y’metres.
Then, at the platform,Distance travelled = y + (length of train) = (y + 480)m
Then, Speed of train = (y + 480)m / (3x60) sec = (y+480)/180 ...(1)
Also, at the pole,Distance travelled = length of train = 480m
Then, Speed of train = 480m / 30sec = 16 m/s ...(2)
Equating eq.(1) & eq.(2), we get,
(y+480)/180 = 16(y+480) = 16 x 180 = 2880
y = 2880 –480 = 2400m or 2.4 km long platform.