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                              Q:
                           
                           
                                                      | A) k=8 & l=2 | B) k=7 & l=2 | 
| C) k=8 & l=3 | D) k=7 & l=1 | 
                              Answer:   B) k=7 & l=2
                              
                                                            
                              
Explanation:
                               
                           
                           Explanation:
If a number to be divisile by 88, it should be divisible by both "8" and "11"
Check for '8' :
For a number to be divisible by "8", the last 3-digit should be divisible by "8"
Here 72x23y --> last 3-digit is '23y'
So y=2 [ (i.e) 232 is absolutely divisible by "8"]
Chech for '11' :
For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"
(7 + x + 3) - (2 + 2 + y)
(7 + x + 3) - (2 + 2 + 2)
(10 + x) - 6 should be divisible by "11"
for x = 7
=> 17 - 6 = 11 [ which is absolutely divisible by "11"]
So x = 7 , y= 2.
                            
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